如何MS SQL Server 2008的

Question

上格式化日期，我想基於像例如22/01/2015或一個2016年12月15日模式格式化日期。

在我們有日期時間在.NET Framework - 它接受格式作爲參數或甚至的String.format，它不相同> ToString（）方法。

是否有格式的日期基礎上論證模式MS SQL Server 2008上的任何功能？

Answer 1

我在SQL 2012類似的問題，他們有一個叫做格式很大的功能，你可以通過在一個日期，你需要

SELECT FORMAT(GETDATE(), 'dd/mm/yyy'); 

把格式有什麼2008年。我創建的SQL Server類似的一個簡單的功能來做類似的工作，它可能需要調整，但不是一個不好的基礎。

-- ============================================= 
-- Author:  Luke Mc Redmond 
-- ============================================= 
CREATE FUNCTION [dbo].[FormatDate] 
(
-- Add the parameters for the function here 
@Date DATETIME, 
@Format NVARCHAR(50) 
) 
RETURNS NVARCHAR(50) 
AS 
BEGIN 

    DECLARE @ResultVar nvarchar(50) = UPPER(@Format); 


    DECLARE @d nvarchar(20) = CONVERT(nvarchar(20), DATEPART(day, @Date)); 
    DECLARE @dd nvarchar(20) = CONVERT(nvarchar(20), DATEPART(day, @Date)); 
    DECLARE @day nvarchar(20) = DATENAME(weekday, @Date); 
    DECLARE @ddd nvarchar(20) = DATENAME(weekday, @Date)+' '+CONVERT(nvarchar(5), DATEPART(day, @Date)); 


    DECLARE @m nvarchar(20) = CONVERT(nvarchar, DATEPART(month, @Date)); 
    DECLARE @mm nvarchar(20) = CONVERT(nvarchar, DATEPART(month, @Date)); 
    DECLARE @mmm nvarchar(20) = CONVERT(VARCHAR(3), DATENAME(month, @Date), 100); 
    DECLARE @month nvarchar(20) = DATENAME(month, @Date); 

    DECLARE @y nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @yy nvarchar(20) = RIGHT(CONVERT(nvarchar, DATEPART(year, GETDATE())),2); 
    DECLARE @yyy nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @yyyy nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 
    DECLARE @year nvarchar(20) = CONVERT(nvarchar, DATEPART(year, @Date)); 

    SELECT @ResultVar = CASE WHEN CHARINDEX('DAY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DAY' collate Latin1_General_CS_AS ,@day) 
         WHEN CHARINDEX('DDD',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DDD' collate Latin1_General_CS_AS ,@ddd) 
         WHEN CHARINDEX('DD',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'DD' collate Latin1_General_CS_AS ,@dd) 
         WHEN CHARINDEX('D',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'D' collate Latin1_General_CS_AS ,@d) END; 

    SELECT @ResultVar = REPLACE(@ResultVar collate Latin1_General_CS_AS,'Monday' collate Latin1_General_CS_AS ,'monday') 

    SELECT @ResultVar = CASE WHEN CHARINDEX('MONTH',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'MONTH' collate Latin1_General_CS_AS,@month) 
         WHEN CHARINDEX('MMM',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'MMM' collate Latin1_General_CS_AS,@mmm) 
         WHEN CHARINDEX('MM',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'MM' collate Latin1_General_CS_AS,@mm) 
         WHEN CHARINDEX('M',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'M' collate Latin1_General_CS_AS,@m) END; 


    SELECT @ResultVar = CASE WHEN CHARINDEX('YEAR',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'YEAR' collate Latin1_General_CS_AS ,@year) 
         WHEN CHARINDEX('YYYY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'YYYY' collate Latin1_General_CS_AS ,@yyyy) 
         WHEN CHARINDEX('YYY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'YYY' collate Latin1_General_CS_AS ,@yyy) 
         WHEN CHARINDEX('YY',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS ,'YY' collate Latin1_General_CS_AS ,@yy) 
         WHEN CHARINDEX('Y',@ResultVar) > 0 THEN REPLACE(@ResultVar collate Latin1_General_CS_AS,'Y' collate Latin1_General_CS_AS ,@y) END; 

    SELECT @ResultVar = REPLACE(@ResultVar collate Latin1_General_CS_AS,'monday' collate Latin1_General_CS_AS ,'Monday') 

    RETURN @ResultVar 

END; 
GO 

希望這有助於！

Answer 2

使用CONVERT函數與風格參數。它全部列在這裏：https://msdn.microsoft.com/en-us/library/ms187928.aspx