-2
我使用html中的select標籤來顯示一些列表。現在，當我從select標籤中選擇一個選項時，我想再次加載表單，並通過所選選項運行另一個查詢，並在另一個選擇標籤中顯示另一個查詢的值。如何在html的select標籤中顯示選中的選項？
選擇任何選項後，它的工作正常我發佈一個類型，我從另一個選擇標籤中獲取另一個數據，但是當我單擊假設選項TSgt和表單重新加載TSgt類型的數據，但選擇選擇標籤顯示爲不是我選擇的MSgt。
如果我如果$類型在_POST陣列設置，並只顯示選擇的標籤不喜歡遵循選擇值不檢查：
<option value="1">SSgt</option>
<option value="2">TSgt</option>
<option value="3">MSgt</option>
然後，選擇默認值顯示警署警長，我想顯示用戶選擇的選擇標籤中的值。
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>MCQ Questions</title>
</head>
<body>
<?php
session_start();
$dbh = new PDO('mysql:host=174.75.54;dbname=handbook', 'airman', 'airman');
$type = $_POST['type'];
$question = $_SESSION["question"];
$optionA = $_SESSION["opt1"];
$optionB = $_SESSION["opt2"];
$optionC = $_SESSION["opt3"];
$optionD = $_SESSION["opt4"];
$ans = $_SESSION["ans"];
$chapter = $_SESSION["chapter"];
?>
<form method="post" action="mcq.php" enctype="multipart/form-data">
<p> Enter the question :</p> <input name="question" type="text"> <br><br>
Select question type :
<select name="type" id="type" onchange="this.form.submit()">
<?php if(isset($_POST['type']))
{ ?>
<option value="1" selected=<?=($type==1?"checked":"");?>>SSgt</option>
<option value="2" selected=<?=($type==2?"checked":"");?>>TSgt</option>
<option value="3" selected=<?=($type==3?"checked":"");?>>MSgt</option>
</select>
<?php
}
else
{
?>
<option value="1">SSgt</option>
<option value="2">TSgt</option>
<option value="3">MSgt</option>
</select>
<?php
}
?>
<br><br>
<?php if(isset($optionA))
{ ?>
<p> Enter options :</p>
Enter option A : <input name="opt1" type="text" value = "<?php echo $optionA?>"</input> <br><br>
<?php
}
else{
?>
<p> Enter options :</p>
Enter option A : <input name="opt1" type="text"> <br><br>
<?php
}
?>
Enter option B : <input name="opt2" type="text"> <br><br>
Enter option C : <input name="opt3" type="text"> <br><br>
Enter option D : <input name="opt4" type="text"> <br><br>
Select correct answer :
<select name="ans" id="type">
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
</select>
<br><br>
Select Chapter :
<select name="chapters" id="chapters">
<?php
if(isset($_POST['type']))
{
$stmt = $dbh->prepare("SELECT * FROM chapters where type = :type");
$stmt->bindParam("type", $type);
$stmt->execute();
$results = $stmt->fetchall(PDO::FETCH_ASSOC);
if(count($results > 0)){
foreach($results as $row):?>
<option value="<?php echo $row['id'];?>"><?php echo $row['title'];?></option>
<?php
endforeach;
}else{?>
<option value="0">No data found</option>
<?php
}
}
else{
$stmt = $dbh->prepare("SELECT * FROM chapters where type = 1");
$stmt->execute();
$results = $stmt->fetchall(PDO::FETCH_ASSOC);
if(count($results > 0)){
foreach($results as $row):?>
<option value="<?php echo $row['id'];?>"><?php echo $row['title'];?></option>
<?php
endforeach;
}else{?>
<option value="0">No data found</option>
<?php
}
}
?>
</select> <br><br>
<input type="submit" value = "Submit">
</form>
</body>
</html>
<?php
// escape post variables
$question = $_POST['question'];
$option1 = $_POST['opt1'];
$option2 = $_POST['opt2'];
$option3 = $_POST['opt3'];
$option4 = $_POST['opt4'];
$ans = $_POST['ans'];
$chapter = $_POST['chapters'];
if(!empty($ans) and !empty($question) and !empty($option1) and !empty($option2) and !empty($option3) and !empty($option4) and !empty($type) and !empty($chapter))
{
$stmt = $dbh->prepare("INSERT INTO questions (question,answer_a,answer_b,answer_c,answer_d,answer,type,chapterId) VALUES (?, ?, ?, ?, ?, ?, ?,?)");
$stmt->execute(array($question, $option1, $option2, $option3, $option4, $ans,$type,$chapter));
if ($dbh->lastInsertId())
{
echo 'Question submitted.';
echo '<a href="mcq.php">Upload another question.</a>';
session_destroy();
}
else
{
echo 'Question could not submit.';
}
}
else{
$_SESSION["question"] = $question;
$_SESSION["chapter"] = $chapter;
$_SESSION["ans"] = $ans;
$_SESSION["opt1"] = $option1;
$_SESSION["opt2"] = $option2;
$_SESSION["opt3"] = $option3;
$_SESSION["opt4"] = $option4;
echo 'Fill all fields.';
}
?>
我不知道這裏出了什麼問題。任何人都可以幫我嗎？
謝謝。
爲選擇它的 「選擇」 而不是 「檢查」 ...！ –