Python：用另一個數組元素作爲鍵來排序數組？

Question

import numpy as np 
x = np.array(range(10 * 30)).reshape(100, 3) 
y = np.array(range(1010, 10, -10)) 
res = sorted(x, key = lambda y:y) #ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() 
res = sorted(x, key=y) #TypeError: 'tuple' object is not callable 

Answer 1

嘗試argsort：

import numpy as np 
x = np.array(range(10 * 30)).reshape(100, 3) 
y = np.array(range(1010, 10, -10)) 
args = y.argsort(axis = 0) 
print x[args]