上面的代碼工作確定:PHP - 使用的preg_replace用的file_get_contents
<?php
function clearPage($content, $class) {
$arr = array(
'@^(.*?)<div class="'.$class.'">(.*?)</div>(.*?)[email protected]' => '<div class="'.$class.'">$2</div>'
);
return preg_replace(array_keys($arr), array_values($arr), $content);
}
$class = "something";
$content = "31xu1823y8<div class="something">Wanted</div>912u38u3"
$result = clearPage($content, $class);
echo $result;
?>
此輸出:
<div class="something">Wanted</div>
但我想使變量的內容,是從網站頁面的HTML代碼。因此,我將最後一個代碼更改爲如下所示:
$class = "something";
$content = file_get_contents('index.php');
$result = clearPage($content, $class);
echo $result;
This outputs all the webpage! Why!?
我猜你會發現在這太問題的答案 - > HTTP:/ /stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags – adeneo
是的,如果你從'input.php'中讀取,你將不會呈現HTML,但PHP只有HTML片段的源代碼。 (正則表達式問題:DOTALL標誌。) – mario