我該如何洗牌變量列表的索引？

Question

如何降低索引列表？用此代碼和變量列表

#turns string to list 
list=[] 
#gets the sentence to count and what to count and deletes punctuation 
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~''' 
sentence=input("Enter sentence to count: ") 
sentence=sentence.lower() 

no_punct = "" 
for char in sentence: 
    if char not in punctuations: 
     no_punct = no_punct + char 

list=no_punct.split() 

#this shows whether it is there or not 
index=[index+1 for index,list in enumerate(list)] 
print("the indices are ",index) 

Answer 1

以下代碼適用於我。 random.shuffle有問題，但我在這裏工作。記住它不會返回任何東西，所以你必須先使用它，然後在洗牌後打印。

import random 

#turns string to list 
list=[] 
#gets the sentence to count and what to count and deletes punctuation 
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~''' 
sentence=input("Enter sentence to count: ") 
sentence=sentence.lower() 

no_punct = "" 
for char in sentence: 
    if char not in punctuations: 
     no_punct = no_punct + char 

list=no_punct.split() 

#this shows whether it is there or not 
index=[index+1 for index,list in enumerate(list)] 
print("the indices are ",index) 

print(index) 
random.shuffle(index) 
print(index) 

編輯：這可能會使它成爲一個重複的問題，如評論中所述。