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我的目標是創建TeamV類型的「TeamS」向量。 TeamV應該有4個部分的數據。例如:TeamV [0] = teamID,member1,member2,member3。 我找到了一種獲取ID數組並分發到TeamV向量的方法。但我無法同時分發3名團隊成員。我該怎麼辦?從二維數組轉換爲矢量
#include <iostream>
#include <vector>
using namespace std;
const int NUM_TEAMS = 4;
const int NUM_MEMBERS = 3;
struct TeamS{
int ID;
string teamMembers[3];
};
void Initialize (vector <TeamS> & TeamV, const int id[],
const string m[][NUM_MEMBERS], int arraySize){
for (int i = 0; i<NUM_TEAMS;i++){
for (int x=0; x<NUM_TEAMS;x++){
for (int y = 0; y<NUM_MEMBERS;y++){
TeamV.push_back({id[i],m[x][y]});
}
}
}
}
int main(){
vector <TeamS> TeamV; //content of arrays below should go in to this vector
const int ID [NUM_TEAMS] ={ 123, 321, 456, 789};
const string MEMBERS [NUM_TEAMS] [NUM_MEMBERS ] =
{
{"Sarah", "Joe", "John"},
{"Chris", "Kevin", "James"},
{"Tom", "Kim", "Emily"},
{"Jill", "Jason", "Jim"}
};
Initialize(TeamV, ID, MEMBERS, NUM_TEAMS*NUM_MEMBERS);
}
你應該做的是初始化數組成員爲'{a,b,c}'。 –
贊[this](https://ideone.com/q4YsvQ)?或者你是否想要複製任意數組? – Drop
我想你在這裏犯了一個錯誤:'TeamV.push_back({id [i],m [x] [y]})'。儘管TeamS結構需要3名團隊成員,但您可以push_back ID和1個團隊成員(x和y位置)。所以當他傳遞TeamS結構時,@Drop的解決方案很好。 –