我要tabels在Access數據庫更新2個tabels領域如何在同一時間
用戶
- 用戶ID
- 用戶名
- useractiv
USERINFO
- userinfoid
- userrealname
- USERPHONE
我然後得到一些ASP的信息:文本字段更新處理程序,我知道如何做到這一點的一個表,但不是2.
通常我用這個
Dim strSQL As String = ""
strSQL = "" & _
"UPDATE Userinfo " & _
"SET userrealname = @therealname, userphone = @theuserphone " & _
"WHERE userinfoid =" & Session("theeditid") & ""
Using connection As OleDbConnection = New OleDbConnection(ConfigurationManager.ConnectionStrings("ConnStr").ConnectionString)
Using updatecmd As OleDbCommand = New OleDbCommand(strSQL, connection)
updatecmd.CommandType = CommandType.Text
updatecmd.Parameters.AddWithValue("@therealname", OleDbType.VarChar).Value = TextBox1.Text
updatecmd.Parameters.AddWithValue("@theuserphone", OleDbType.VarChar).Value = CKEditor1.Text
Try
updatecmd.Connection.Open()
Dim i As Integer = CInt(updatecmd.ExecuteNonQuery())
If i = 0 Then
Session("editsucces") = "NoMatch" 'no rows were updated because none matched the criteria
End If
Catch ex As Exception
Session("editsucces") = "DBerror" 'Something went wrong, such as the database was unavailable
End Try
End Using
End Using
所以我的問題是現在,我如何從用戶TABEL加場!? user.userid與userinfo.userinfoid中的數字相同。
編輯........編輯........編輯.......編輯.........編輯........ .EDIT ..........編輯
所以這段代碼是好的,或者你重新考慮我改變了一些!?
Dim strSQL As String = ""
strSQL = "" & _
"UPDATE Users INNER JOIN Userinfo ON Users.UserID = Userinfo.UserID " & _
"SET Users.Username = [@uname], Users.Password = [@upass], Users.UserActiv = [@uactiv], Userinfo.UserRealName = [@urname], Userinfo.UserEmail1 = [@umail], Userinfo.UserDOB = [@udob], Userinfo.UserPhone1 = [@uphone1], Userinfo.UserPhone2 = [@uphone2], Userinfo.UserPhone3 = [@uphone3], Userinfo.UserYear = [@uyear], Userinfo.UserSick = [@usick] " & _
"WHERE Users.UserID = [@uid]"
Using connection As OleDbConnection = New OleDbConnection(ConfigurationManager.ConnectionStrings("ConnStr").ConnectionString)
Using updatecmd As OleDbCommand = New OleDbCommand(strSQL, connection)
updatecmd.CommandType = CommandType.Text
updatecmd.Parameters.AddWithValue("@uname", OleDbType.VarChar).Value = userinput1.Text
updatecmd.Parameters.AddWithValue("@upass", OleDbType.VarChar).Value = userinput2.Text
updatecmd.Parameters.AddWithValue("@uactiv", OleDbType.VarChar).Value = "Y"
updatecmd.Parameters.AddWithValue("@urname", OleDbType.VarChar).Value = userinput3.Text
updatecmd.Parameters.AddWithValue("@umail", OleDbType.VarChar).Value = userinput4.Text
updatecmd.Parameters.AddWithValue("@udob", OleDbType.VarChar).Value = userinput5.Text
updatecmd.Parameters.AddWithValue("@uphone1", OleDbType.VarChar).Value = userinput6.Text
updatecmd.Parameters.AddWithValue("@uphone2", OleDbType.VarChar).Value = userinput7.Text
updatecmd.Parameters.AddWithValue("@uphone3", OleDbType.VarChar).Value = userinput8.Text
updatecmd.Parameters.AddWithValue("@uyear", OleDbType.VarChar).Value = userinput9.Text
updatecmd.Parameters.AddWithValue("@usick", OleDbType.VarChar).Value = usertextarea.Text
Try
updatecmd.Connection.Open()
Dim i As Integer = CInt(updatecmd.ExecuteNonQuery())
If i = 0 Then
Session("editsucces") = "NoMatch" 'no rows were updated because none matched the criteria
End If
Catch ex As Exception
Session("editsucces") = "DBerror" 'Something went wrong, such as the database was unavailable
End Try
End Using
End Using
Response.Redirect("default.aspx", False)
您好我用在WHERE userinfoid =」&會議( 「theeditid」)& 「」 話,那麼它就知道我需要的user.userid多數民衆贊成也許3!? –
最後,我會添加一個註釋 – Fionnuala
嗨,再次,所以編輯行下的代碼是OK!?或..... –