2017-10-20 82 views
1

我的用例是編寫在postgres數據庫中創建臨時表,並從中獲取記錄並插入到不同的表中。Python代碼不在數據庫上創建表,但能夠查詢結果postgres

我使用的代碼是:

import psycopg2 
import sys 
import pprint 

from __future__ import print_function 
from os.path import join,dirname,abspath 
import xlrd 
import os.path 

newlist = [] 
itemidlist = [] 

def main(): 

    conn_string = "host='prod-dump.cvv9i14mrv4k.us-east-1.rds.amazonaws.com' dbname='ebdb' user='ebroot' password='*********'" 
    # print the connection string we will use to connect 
    # print "Connecting to database" % (conn_string) 

    # get a connection, if a connect cannot be made an exception will be raised here 
    conn = psycopg2.connect(conn_string) 

    # conn.cursor will return a cursor object, you can use this cursor to perform queries 
    cursor = conn.cursor() 

    dealer_id = input("Please enter dealer_id: ") 
    group_id = input("Please enter group_id: ") 

    scriptpath = os.path.dirname('__file__') 
    filename = os.path.join(scriptpath, 'Winco - Gusti.xlsx') 

    xl_workbook = xlrd.open_workbook(filename, "rb") 

    xl_sheet = xl_workbook.sheet_by_index(0) 
    print('Sheet Name: %s' % xl_sheet.name) 

    row=xl_sheet.row(0) 

    from xlrd.sheet import ctype_text 

    print('(Column #) type:value') 
    for idx, cell_obj in enumerate(row): 
     cell_type_str = ctype_text.get(cell_obj.ctype, 'unknown type') 
     #print('(%s) %s %s' % (idx, cell_type_str, cell_obj.value)) 

    num_cols = xl_sheet.ncols 

    for row_idx in range(0, xl_sheet.nrows): # Iterate through rows 
     num_cols = xl_sheet.ncols 

     id_obj = xl_sheet.cell(row_idx, 1) # Get cell object by row, col 
     itemid = id_obj.value 
     #if itemid not in itemidlist: 
     itemidlist.append(itemid) 

     # execute our Query 
     ''' 
     cursor.execute(""" 
     if not exists(SELECT 1 FROM model_enable AS c WHERE c.name = %s); 
     BEGIN; 
      INSERT INTO model_enable (name) VALUES (%s) 
     END; 
     """ %(itemid,itemid)) 
     '''  
    cursor.execute("drop table temp_mbp1") 

    try: 
     cursor.execute("SELECT p.model_no, pc.id as PCid, g.id AS GROUPid into public.temp_mbp1 FROM products p, \ 
     model_enable me, products_clients pc, groups g WHERE p.model_no = me.name \ 
     and p.id = pc.product_id and pc.client_id = %s and pc.client_id = g.client_id and g.id = %s"\ 
     % (dealer_id,group_id) 

    except (Exception, psycopg2.DatabaseError) as error: 
     print(error) 

    cursor.execute("select count(*) from public.temp_mbp1") 
    # retrieve the records from the database 
    records = cursor.fetchall() 

    # print out the records using pretty print 
    # note that the NAMES of the columns are not shown, instead just indexes. 
    # for most people this isn't very useful so we'll show you how to return 
    # columns as a dictionary (hash) in the next example. 
    pprint.pprint(records) 

if __name__ == "__main__": 
     main() 

中的程序沒有拋出任何錯誤,但不是Postgres數據庫越來越創建的表,因爲我在數據管理看,除了塊的嘗試。

顯示的輸出:

Please enter dealer_id: 90 
Please enter group_id: 13 
Sheet Name: Winco Full 8_15_17 
(Column #) type:value 
[(3263,)] 

感謝,桑托斯

+0

pprint(records)語句是否顯示任何內容? – chasmani

+0

是的。它顯示輸出。 – lifeofpy

回答

2

你沒有提交更改,所以它們不會被保存在數據庫中。添加到底部,正下方的pprint聲明:

conn.commit()