這個問題是一個幾個月大,但如果你還在尋找一個答案,這是我試過的工作:
class Source
{
public string Name { get; set; }
public Inner Inner { get; set; }
}
class Inner
{
public Col A { get; set; }
public Col B { get; set; }
}
class Col : List<ClassX> { }
class ClassX
{
public int Index { get; set; }
public string Name { get; set; }
public ClassX() : this(0, "") { }
public ClassX(int index, string name)
{
this.Index = index;
this.Name = name;
}
}
class ClassY
{
public int Index { get; set; }
public string Name { get; set; }
public ClassY() : this(0, "") { }
public ClassY(int index, string name)
{
this.Index = index;
this.Name = name;
}
}
class Dest
{
public string Name { get; set; }
public List<ClassY> A { get; set; }
public List<ClassY> B { get; set; }
}
[TestMethod]
public void ComplexTest()
{
Mapper.CreateMap<Source, Dest>()
.ForMember(dest => dest.A, config => config.MapFrom(src => src.Inner.A))
.ForMember(dest => dest.B, config => config.MapFrom(src => src.Inner.B));
Mapper.CreateMap<ClassX, ClassY>();
Source source = new Source
{
Name = "Source",
Inner = new Inner
{
A = new Col
{
new ClassX(1, "First"),
new ClassX(2, "Second"),
new ClassX(3, "Third"),
new ClassX(4, "Fourth"),
},
B = new Col
{
new ClassX(5, "Fifth"),
new ClassX(6, "Sixth"),
new ClassX(7, "Seventh"),
new ClassX(8, "Eighth"),
},
}
};
Dest destination = Mapper.Map<Source, Dest>(source);
Assert.AreEqual(source.Name, destination.Name);
Assert.AreEqual(source.Inner.A.Count, destination.A.Count);
Assert.AreEqual(source.Inner.B.Count, destination.B.Count);
Assert.AreEqual(source.Inner.A[0].Name, destination.A[0].Name);
Assert.AreEqual(source.Inner.B[0].Name, destination.B[0].Name);
}
我沒去太深入我的斷言,所以可能有一些我錯過了,但他們似乎被正確映射。
澄清:你希望dest.name來自source.name和dest.A來自source.Inner.A和dest.B來自source.Inner.B? – PatrickSteele 2010-09-10 23:12:03
帕特里克,是的,這是我追求的行爲。 – gsogol 2010-09-12 17:49:15