Json解析IOS中的錯誤

您好，我有一些問題解析IOS中的JSON。這是json數據。Json解析IOS中的錯誤

{ 
"app_info": [ 
    { 
     "app_name": "haka", 
     "sync_protocol_version": "1" 
    } 
], 
"updates": [ 
    { 
     "timestamp": "Sat Apr 21 13:04:08 IST 2012", 
     "people": [ 
      { 
       "personal_info": [ 
        { 
         "first_name": "phlox", 
         "last_name": "", 
         "employee_id": "010", 
         "gender": "-", 
         "marital_status": "-", 
         "nationality": "Denobulan", 
         "dob": "re-23", 
         "photo": "http://c.cc/users/010/profile/image" 
        } 
       ], 
       "contact_details": [ 
        { 
         "address": [ 
          { 
           "street": "#1, this way", 
           "city": "tank", 
           "state": "sick bay", 
           "zip": "0978", 
           "country": "Enterprise" 
          } 
         ], 
         "telephone": [ 
          { 
           "work": "010", 
           "mobile": "010", 
           "home": "010" 
          } 
         ], 
         "email": [ 
          { 
           "work": "[email protected]", 
           "personal": "" 
          } 
         ] 
        } 
       ], 
       "emergency": [ 
        { 
         "contact": [ 
          { 
           "name": "-", 
           "relationship": "", 
           "telephone": [ 
            { 
             "work": "", 
             "home": "", 
             "mobile": "" 
            } 
           ] 
          } 
         ], 
         "blood_group": "" 
        } 
       ], 
       "categorization": [ 
        { 
         "designation": "", 
         "department": "", 
         "location": "", 
         "joining_date": "" 
        } 
       ] 
      }, 
      { 
       "personal_info": [ 
        { 
         "first_name": "", 
         "last_name": "", 
         "employee_id": "", 
         "gender": "", 
         "marital_status": "", 
         "nationality": "", 
         "dob": "", 
         "photo": "" 
        } 
       ], 
       "contact_details": [ 
        { 
         "address": [ 
          { 
           "street": "", 
           "city": "", 
           "state": "", 
           "zip": "", 
           "country": "" 
          } 
         ], 
         "telephone": [ 
          { 
           "work": "", 
           "mobile": "", 
           "home": "" 
          } 
         ], 
         "email": [ 
          { 
           "work": "", 
           "personal": "" 
          } 
         ] 
        } 
       ], 
       "emergency": [ 
        { 
         "contact": [ 
          { 
           "name": "", 
           "relationship": "", 
           "telephone": [ 
            { 
             "work": "", 
             "home": "", 
             "mobile": "" 
            } 
           ] 
          } 
         ], 
         "blood_group": "" 
        } 
       ], 
       "categorization": [ 
        { 
         "designation": "", 
         "department": "", 
         "location": "", 
         "joining_date": "" 
        } 
       ] 
      } 
     ], 
     "messages": [ 
      { 
       "sender": "Archer<[email protected]>", 
       "sender_role": "admin", 
       "message_type": "broadcast", 
       "message": "parking space up for grabs", 
       "message_recipients": "all", 
       "reply_permitted": "0" 
      } 
     ], 
     "events": [ 
      { 
       "creator": "Travis<[email protected]>", 
       "event_title": "", 
       "event_description": "", 
       "event_time_start": "", 
       "event_time_end": "", 
       "location": "", 
       "invitees": [ 
        { 
         "id": "020", 
         "acceptance": "1" 
        } 
       ] 
      } 
     ], 
     "settings": [ 
      { 
       "sync_frequency": "0" 
      } 
     ] 
    } 
]}

這是一個有效的json格式。我曾與http://jsonlint.com/檢查，並使用http://braincast.nl/samples/jsoneditor/

看到JSON value.According的結構，結構的人標記應返回2的計數，因爲它具有2個對象，但它只返回1，而解析。我完全沒有選擇。請幫助傢伙。

這是我使用的代碼解析

NSString *textPAth = [[NSBundle mainBundle] pathForResource:@"sync" ofType:@"json"]; 
NSError *error; 
NSString *content = [NSString stringWithContentsOfFile:textPAth encoding:NSUTF8StringEncoding error:&error];  
NSArray *jsonArray = [[content JSONValue] retain]; 
NSLog(@"JSON ARRAY %@ AND COUNT %d",[[jsonArray valueForKey:@"updates"] valueForKey:@"people"],[[[jsonArray valueForKey:@"updates"] valueForKey:@"people"] count]);

來源

2012-05-02 arindam

我不知道爲什麼每次字典是包裹着一個數組，當只有1項（不必要的），但是如果你要分析它，你想要的東西是這樣的：

NSDictionary *jsonDict = [[content JSONValue] retain]; 
NSArray *updatesArray = [jsonDict objectForKey:@"updates"]; 
NSDictionary *updatesDict = [updatesArray objectAtIndex:0]; 
NSArray *peopleArray = [updatesDict objectForKey:@"people"]; 
NSLog(@"People count: %i", [peopleArray count]); 
for (NSDictionary *peopleDict in peopleArray) { 
    //do something 
}

作爲一個方面說明，如果這是你的JSON，你會想要刪除[數組]的實際上不是數組的條目。雖然仍然可以解析它，但這意味着您必須先讀取數組，然後從objectAtIndex：0中獲取字典，這是完全沒有效率和毫無意義的。

來源

2012-05-02 21:04:16 Joel

+1這應該是正確的答案。一面說明;當解析JSON數據並期望數組時，您可能會發現令人討厭的驚喜，具體取決於JSON呈現（通常在服務器端）。對於這樣的JSON渲染器來說，它實際上提供了一個只包含單個對象而不是數組的對象。參見例如[PHP的json_encode]（http://www.php.net/manual/en/function.json-encode.php）。 – Till

好點。我只是給他這個特殊例子的快速和骯髒的解析（沒有錯誤檢查/防守代碼）。 – Joel

謝謝喬爾。它的工作完美。我完全同意蒂爾。 – arindam

會不會是你的對象中的每一個被包裹在一個陣列，並給予意想不到的結果？

來源

2012-05-02 21:01:53 nathanjosiah

Json解析IOS中的錯誤

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