數據庫創建使用PHP和MySQL

Question

好了，我有這樣的代碼：

<?php 
$dbhost = 'localhost'; 
$dbuser = 'root'; 
$dbpwd = 'ALLO'; 
$dbname = 'test'; 
$conn = mysqli_connect($dbhost, $dbuser, $dbpwd, $dbname); 


if(! $conn) 
{ 
    die("\nconn: $conn \nCould not connect: " . mysqli_error($conn)); 
} 
echo "\n"; 







$createtab="CREATE TABLE People(FirstName CHAR(30),LastName CHAR(30),Age INT)"; 

// Execute query 
if (mysqli_query($conn,$createtab)) 
    { 
    echo "Table created successfully"; 
    } 
else 
    { 
    echo "Error creating table: " . mysqli_error($conn); 
    } 

echo "\n"; 




mysqli_query($conn,"INSERT INTO People (FirstName, LastName, Age) 
VALUES ('Peter', 'Griffin',35)"); 

mysqli_query($conn,"INSERT INTO People (FirstName, LastName, Age) 
VALUES ('Glenn', 'Quagmire',33)"); 






mysqli_close($conn) 
?> 

當我運行PHP腳本，它運行良好。

但是，我無法在mysql工作臺中找到表。

我刷新了很多次。

http://i.stack.imgur.com/uX1sQ.png http://i.stack.imgur.com/iEXqT.png

Answer 1

看看這給你任何結果：

SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME='People' 

如果不是，任何表之前創建一個數據庫，或者從你的截圖來看只是在你的代碼中添加使用的測試。

$createdb="USE test"; 

// Execute query 
if (mysqli_query($conn,$createdb)) 
{ 
    echo "Db selected"; 
} 
else 
{ 
    echo "Error selecting db: " . mysqli_error($conn); 
}