Python字典生成，需要解壓的變量太多

Question

嘗試從.csv文件解析的數據列表中生成字典。獲取錯誤「太多的值解包」，任何想法修復？

將會有重複鍵/多重值附加到每個鍵。

我很新的python和編程，所以請如果你可以添加一個簡短的解釋出了什麼問題/如何解決。

腳本下方是打印res時的數據。

#!/usr/bin/python 
import csv 
import pprint 
pp = pprint.PrettyPrinter(indent=4) 
import sys 
import getopt 
res = [] 

import argparse 
parser = argparse.ArgumentParser() 

parser.add_argument ("infile", metavar="CSV", nargs="+", type=str, help="data file") 
args = parser.parse_args() 

with open("out.csv","wb") as f: 
    output = csv.writer(f) 
    for filename in args.infile: 
     for line in csv.reader(open(filename)): 
      for item in line[2:]: 

       #to skip empty cells 
       if not item.strip(): 
        continue 

       item = item.split(":") 
       item[1] = item[1].rstrip("%") 

#    print([line[1]+item[0],item[1]]) 
       res.append([line[1]+item[0],item[1]]) 
#    output.writerow([line[1]+item[0],item[1].rstrip("%")]) 

pp.pprint(res) 

from collections import defaultdict 
initial_list = [res] 

d = defaultdict(list) 
pp.pprint(d) 
for k, v in initial_list: 
    d[k].append(float(v)) # possibly `int(v)` ? 

和控制檯

[ ['P1L', '2.04'], 
    ['Q2R', '1.93'], 
    ['V3I', '20.03'], 
    ['V3M', '78.18'], 
    ['V3S', '1.67'], 
    ['T4L', '1.16'], 
    ['T12N', '75.60'], 
    ['T12S', '22.73'], 
    ['K14E', '1.03'], 
    ['K14R', '50.65'], 
    ['I15*', '63.94'], 
    ['I15V', '35.30'], 
    ['G17A', '38.31'], 
    ['Q18R', '38.43'], 
    ['L19T', '98.62'], 
    ['L24*', '2.18'], 
    ['D25E', '1.87'], 
    ['D25N', '2.17'], 
    ['M36I', '99.76'], 
    ['S37N', '97.23'], 
    ['R41K', '99.03'], 
    ['L63V', '99.42'], 
    ['H69K', '99.30'], 
    ['I72V', '5.76'], 
    ['V82I', '98.70'], 
    ['L89M', '98.49'], 
    ['I93L', '99.64'], 
    ['P4S', '99.09'], 
    ['V35T', '99.26'], 
    ['E36A', '98.23'], 
    ['T39D', '98.78'], 
    ['G45R', '3.11'], 
    ['S48T', '99.70'], 
    ['V60I', '99.44'], 
    ['K102R', '1.04'], 
    ['K103N', '99.11'], 
    ['G112E', '2.77'], 
    ['D123N', '8.14'], 
    ['D123S', '91.12'], 
    ['I132M', '1.41'], 
    ['K173A', '99.55'], 
    ['Q174K', '99.68'], 
    ['D177E', '98.95'], 
    ['G190R', '2.56'], 
    ['E194K', '2.54'], 
    ['T200A', '99.28'], 
    ['Q207E', '98.75'], 
    ['R211K', '98.77'], 
    ['W212*', '3.00'], 
    ['L214F', '99.25'], 
    ['V245E', '99.30'], 
    ['E248D', '99.58'], 
    ['D250E', '99.02'], 
    ['T286A', '99.70'], 
    ['K287R', '1.78'], 
    ['E291D', '99.22'], 
    ['V292I', '98.28'], 
    ['I293V', '99.58'], 
    ['V317A', '28.20'], 
    ['L325V', '2.40'], 
    ['G335D', '98.33'], 
    ['F346S', '4.42'], 
    ['N348I', '3.81'], 
    ['R356K', '71.43'], 
    ['M357I', '20.00'], 
    ['M357T', '80.00']] 
defaultdict(<type 'list'>, {}) 
Traceback (most recent call last): 
    File "test.py", line 40, in <module 
    for k, v in initial_list: 
ValueError: too many values to unpack 

Answer 1

你包裹的結果列表：

initial_list = [res] 

然後嘗試遍歷列表：

d = defaultdict(list) 
pp.pprint(d) 
for k, v in initial_list: 
    d[k].append(float(v)) # possibly `int(v)` ? 

你想循環res inst EAD：

d = defaultdict(list) 
for k, v in res: 
    d[k].append(float(v)) 

你可以做到這一切在CSV閱讀循環：

from collections import defaultdict 
d = defaultdict(list) 

with open("out.csv","wb") as f: 
    output = csv.writer(f) 
    for filename in args.infile: 
     for line in csv.reader(open(filename)): 
      for item in line[2:]: 

       #to skip empty cells 
       if not item.strip(): 
        continue 

       key, value = item.split(":", 1) 
       value = value.rstrip("%") 

       d[line1[1] + key].append(float(value))