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我有3個表: -Laravel訪問值對象
available_offers - ID
- 最新
- 時間
- 從
- 以
- USER_ID
requested_offer - id
- user_id
- available_offersID
用戶 - ID
- 姓名
- 用戶名
- 密碼
- 電子郵件
這裏我routes_bookedController
class routes_bookedController extends Controller
{
public function create()
{
$user = available_offers::with('user')->get();
$booked = requested_routes::with('available_offers', 'user')
->where('user_id', Auth::id())
->get();
return $booked;
return view ('routes_booked.show', compact('booked'));
}
}
這裏從show.blade.php結果from routes_bookedController
[
{
"id": 3,
"user_id": 4,
"available_offersID": 3,
"created_at": null,
"updated_at": null,
"available_offers": {
"id": 3,
"date": "2017-08-08",
"time": "14:11:30",
"from": "Sabah",
"to": "Sarawak",
"user_id": 2,
"isBooked": 1,
"created_at": null,
"updated_at": null
},
"user": {
"id": 4,
"name": "admin",
"username": "user1",
"email": "[email protected]",
"created_at": "2017-08-08 06:15:49",
"updated_at": "2017-08-08 06:15:49"
}
}
]
是否可以從available_offers-> user-> name中獲取名稱?
這是我的模型: -
requested_routes
class requested_routes extends Model { public function available_offers() { return $this->belongsTo(available_offers::class, 'available_offersID'); } public function user() { return $this->belongsTo(User::class); } }
available_offers
class available_offers extends Model { public function user() { return $this->belongsTo(User::class); } public function requested_routes() { return $this->hasMany(requested_routes::class); } }
用戶
public function available_offers() { return $this->hasMany(available_offers::class); } public function requested_routes() { return $this->hasMany(requested_routes::class); }
是的,這應該工作得很好。 – Jerodev
它應該工作,因爲當你dded你可以看到用戶對象具有屬性名稱等於管理員,所以它應該輸出管理員。 –