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下面顯示了我的HTML & PHP對於頁面上的大多數標記(包括while循環)。它循環出sql表中的所有行,用戶應該能夠點擊圖像,並打開一個模式,以便能夠裁剪該圖像。這在頁面上的第一個項目(第一個sql行)中工作得很好,但對於所有後續的sql行,單擊後模塊不會打開。我該如何糾正或排除故障?如何允許在PHP While循環中切換Twitter Bootstrap模態
我使用的Twit BS 3.2.0
<?php
ob_start();
session_start();
require_once ('verify.php');
?>
<head>
<title>Edit Listings</title>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css" rel="stylesheet">
<link href="../css/cropper.min.css" rel="stylesheet">
<link href="../css/crop-avatar.css" rel="stylesheet">
</head>
<body>
<div id="container">
<div id="head">
<ul id="menu">
</ul>
</div>
<div id="area"></div>
<div id="main_listings">
<h1 align="left">Edit listings page</h1>
<?php
include ("../dbcon2.php");
$conn = new mysqli($servername, $username, $password, $dbname);
$sql="SELECT * FROM listings ORDER BY date_added DESC";
$result = $conn->query($sql);
?>
<?php while ($data=mysqli_fetch_assoc($result)):
$id = $data['id'];
$title = $data['title'];
$listing_img = $data['listing_img'];
?>
<div id="edit_listing">
<div id="edit_left">
<div class="container" id="crop-avatar">
<div class="avatar-view" title="Change the avatar"> <img src="<?php echo $listing_img; ?>" alt="<?php echo $title; ?>"> </div>
<div class="modal fade" id="avatar-modal" tabindex="-1" role="dialog" aria-labelledby="avatar-modal-label" aria-hidden="true">
<div class="modal-dialog modal-lg">
<div class="modal-content">
<form class="avatar-form" method="post" action="edit-avatar.php" enctype="multipart/form-data">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title" id="avatar-modal-label">Listing Main Image</h4>
</div>
<div class="modal-body">
<div class="avatar-body">
<div class="avatar-upload">
<input class="avatar-src" name="avatar_src" type="hidden">
<input class="avatar-data" name="avatar_data" type="hidden">
<input name="avatar_id" type="hidden" value="<?php echo $id; ?>">
<label for="avatarInput">Local upload</label>
<input class="avatar-input" id="avatarInput" name="avatar_file" type="file">
</div>
<div class="row">
<div class="col-md-9">
<div class="avatar-wrapper"></div>
</div>
<div class="col-md-3">
<div class="avatar-preview preview-lg"></div>
</div>
</div>
</div>
</div>
<div class="modal-footer">
<button class="btn btn-default" type="button" data-dismiss="modal">Close</button>
<button class="btn btn-primary avatar-save" type="submit">Save</button>
</div>
</form>
</div>
</div>
</div>
<div class="loading" tabindex="-1" role="img" aria-label="Loading"></div>
</div>
</div>
<div id="edit_right">
<form name="edit_date" action="edit_list.php" method="post" id="edit_list_data">
<input name="title" type="text" id="title" tabindex="1" value="<?php echo $title; ?>" size="60" maxlength="57"/>
<input type="hidden" name="id" value="<?php echo $id; ?>" />
<input type="submit" formaction="edit_list.php" value="Submit" />
</form>
</div>
</div>
<?php endwhile;$conn->close();?>
<div class="spacer"></div>
</div>
</div>
<script src="//code.jquery.com/jquery-1.11.1.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script>
<script src="../js/cropper.min.js"></script>
<script src="../js/crop-avatar.js"></script>
</body>
</html><?php // Flush the buffered output.
ob_end_flush();
?>
爲什麼要設置$ id = $ data ['id'],然後直接用$ data ['title']替換該值? – commanderZiltoid 2014-11-21 20:26:34
@nullReference錯誤,當我最小化我的代碼爲StackO。修復,謝謝 – rhill45 2014-11-21 20:36:08