2016-02-12 50 views

回答

1

updateLine()函數將數據作爲參數。數據格式向前將所有語音信箱是:

$data = array("pattern"=>$extension,"callForwardAll"=>array("forwardToVoiceMail"=true)) 

HOWTO文章 https://developer.cisco.com/site/axl/learn/how-to/index.gsp

創建PHP SOAP客戶端需要https://developer.cisco.com/site/axl/develop-and-test/documentation/latest-version/axl-soap.gsp

+0

我嘗試https://developer.cisco.com/site/axl/learn/how-to/axl-php-primer.gsp

與數據結構信息的所有可用的功能那麼,但我得到這個錯誤:未捕獲SoapFault異常:[WSDL] SOAP錯誤:解析WSDL:無法從'AXLAPI.wsdl'加載:無法加載外部實體「AX LAPI.wsdl「 –

+0

忽略最後一條評論我明白了。代碼工作,感謝您的詳細和鏈接! –