javax.el.ELException：無法解析表達式[$ {fn：escapeXml（user.lastName）+ ='，'+ = fn：escapeXml（user.firstName）}]

我想創建簡單的項目tomcat7通過eclipse。這裏是我的JSP頁面的代碼：

<%@ page language="java" contentType="text/html; charset=UTF-8" 
    pageEncoding="UTF-8"%> 
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
<title>Insert title here</title> 
</head> 
    <body> 
     User ID: ${user.userId}<br /> 
     Username: ${user.username} (${user.username.length()} characters)<br /> 
     Full Name: ${fn:escapeXml(user.lastName) += ', ' 
      += fn:escapeXml(user.firstName)} 
     <br /><br /> 
     <b>Permissions (${fn:length(user.permissions)})</b><br /> 
     User: ${user.permissions["user"]}<br /> 
     Moderator: ${user.permissions["moderator"]}<br /> 
     Administrator: ${user.permissions["admin"]}<br /> 
    </body> 
</html>

下面是從瀏覽器窗口中的結果：

org.apache.jasper.JasperException: javax.el.ELException: Failed to parse the expression [${fn:escapeXml(user.lastName) += ', ' 
     += fn:escapeXml(user.firstName)}] 
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549) 
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470) 
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) 
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
ProfileServlet.doGet(ProfileServlet.java:46) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:620) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 

root cause 

javax.el.ELException: Failed to parse the expression [${fn:escapeXml(user.lastName) += ', ' 
     += fn:escapeXml(user.firstName)}] 
org.apache.el.lang.ExpressionBuilder.createNodeInternal(ExpressionBuilder.java:145) 
org.apache.el.lang.ExpressionBuilder.build(ExpressionBuilder.java:171) 
org.apache.el.lang.ExpressionBuilder.createValueExpression(ExpressionBuilder.java:216) 
org.apache.el.ExpressionFactoryImpl.createValueExpression(ExpressionFactoryImpl.java:66) 
org.apache.jasper.runtime.PageContextImpl.proprietaryEvaluate(PageContextImpl.java:943) 
org.apache.jsp.WEB_002dINF.jsp.view.profile_jsp._jspService(profile_jsp.java:96) 
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) 
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) 
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
ProfileServlet.doGet(ProfileServlet.java:46) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:620) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 

    root cause 

    org.apache.el.parser.ParseException: Encountered " <ILLEGAL_CHARACTER> "= "" at line 1, column 32.

目標運行時設置（tomcat7）。可能在我的tomcat7/lib目錄中出錯了？（JSTL 1.2 JAR文件夾內）

而且，這裏是從base.jspf進口（這是所有的JSP頭）

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %> 
    <%@ taglib prefix="fn" uri="http://java.sun.com/jsp/jstl/functions" %>

「常規」 JSTL標記工作。與功能

來源

2016-06-21 kurumkan

爲什麼'+ ='？你嘗試了一個簡單的'+'嗎？請注意，'FN：escapeXml（user.lastName +'，'+ user.firstName）'使事情更具可讀性恕我直言 – 2016-06-21 05:37:52

是的，我試過了。但同樣的信息仍然存在。是的，我也認爲你的方法更具可讀性。但它只是一本書 – kurumkan

的教程，可能是lib文件夾中的jasper *文件有問題？不知道該怎麼辦 – kurumkan

問題嘗試使用core:out這樣的：

<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> 
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%> 
<%@ taglib prefix="fn" uri="http://java.sun.com/jsp/jstl/functions"%> 
<!DOCTYPE html> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
<title>Insert title here</title> 
</head> 
<body> 
    User ID: <c:out value="${user.userId}" /> 
    <br /> Username: <c:out value="${user.username}" /> (<c:out value="${user.username.length}" /> characters) 
    <br /> Full Name: <c:out value="${user.lastName}" />, <c:out value="${user.firstName}" /> 
    <br /> 
    <br /> 
    <b>Permissions (${fn:length(user.permissions)})</b> 
    <br /> User: <c:out value="${user.permissions.user}" /> 
    <br /> Moderator: <c:out value="${user.permissions.moderator}" /> 
    <br /> Administrator: <c:out value="${user.permissions.admin}" /> 
    <br /> 
</body> 
</html>

它工作正常，我和它在默認情況下逃脫XML。

來源

2016-06-21 05:58:48 neomega

javax.el.E​​LException：無法解析表達式[$ {fn：escapeXml（user.lastName）+ ='，'+ = fn：escapeXml（user.firstName）}]

回答

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javax.el.ELException：無法解析表達式[$ {fn：escapeXml（user.lastName）+ ='，'+ = fn：escapeXml（user.firstName）}]