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我是編程新手，剛剛開始執行uva問題。在問題11403中，無論我做什麼，我的提交結果始終是運行時錯誤。我不明白的地方是我的問題，或者爲什麼會導致errors.Can請人幫忙Uva中的運行時錯誤11403
/*
* File Name: Main.java
* ---------------------------------------
* This program will take two binary number as input
* then multiply those number and show the result and
* also the procedure
* 11
* 11
* ---
* 11
* 11x
* ------
* 1001
*/
import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
while(input.hasNext())
{
int num1=input.nextInt();
int num2=input.nextInt();
if(num1==0 && num2==0) break;
String []answers=multiply(num1,num2);//will return a array with the mid answers and the main answer
int answerlen=answers[answers.length-1].length();//The last element of the array will contain the answer
printQuestion(num1,num2,answerlen);//will print the question
printAnswers(answers,answerlen);
}
}
/*
* Will multiply the given binary digits and return the answers in String array
*
* @param first the first binary number
* @param second the second binary number
* @returns a String array with the mid multiply answers and the main answer
*/
public static String [] multiply(int first, int second)
{
String temp=""+second;//to turn second number into string
String[] answers=new String[temp.length()+1];//creating a array with size +one then second number length
int [] midans=new int[temp.length()];//creating a array of size same as second number length
int ten=1; // a variable to hold tens power
for(int i=second,j=0; 0<i ; i=i/10,j++)
{
int section=i%10; // will section the second number like if 11 will make it 1
midans[j]=first*section;
if(midans[j]==0)
{
answers[j]="";
for(int x=first;x>0;x=x/10)
{
answers[j]+=midans[j];
}
}
else answers[j]=""+midans[j];//saving the middle answer
midans[j]*=ten;//multiplying the numbers with the power of ten so each level have same number of zero as its level number
ten*=10;//increasing the zero
}
String finalans="";//a temporary variable to save the answer
int carry=0;//to save the carry found by doing addition
for(int i=midans[midans.length-1]; 0<i;i=i/10)//a loop that will run as many as the last level number with zero
{
int temp1=0;//to help in addition
for(int j=second,k=0; 0<j;j=j/10,k++)//will run as many digit as second number have
{
int add=midans[k]%10;//getting the last digit of the mid answer
midans[k]=midans[k]/(10);//making it a digit shorter
if(k==0)
{
//if its the first time that carry will be added
temp1+=add+carry;
carry=0;
}
else
{
temp1+=add;
}
for(;temp1>=2;temp1-=2)
{
//if temp is greater or equal thn two then we count the carry
carry++;
}
}
if(i/10==0 && carry !=0)
{
//for the last carry which will be placed at first
finalans+=temp1;
finalans+=carry;
}
else
{
finalans+=temp1;
}
}
char [] tempans=finalans.toCharArray();
answers[answers.length-1]="";
/*
* to reverse the answer and save the real answer in the last
* index of answers array;
*/
for(int i=0 ;i<tempans.length;i++)
{
answers[answers.length-1]+=""+tempans[tempans.length-1-i];
}
return answers;
}
/*
* will print the question
*/
public static void printQuestion(int one,int two,int length)
{
String first=""+one;
String second=""+two;
for(int j=0 ; j<(length-first.length()) ; j++)
{
System.out.print(" ");
}
System.out.println(one);
for(int j=0 ; j<(length-second.length()) ; j++)
{
System.out.print(" ");
}
System.out.println(second);
for(int j=0 ; j<(length-second.length()) ; j++)
{
System.out.print(" ");
}
for(int j=0 ; j<(second.length()) ; j++)
{
System.out.print("-");
}
System.out.println();
}
/*
* Printing answers
*/
public static void printAnswers(String [] answers ,int length)
{
for(int i=0 ;i<answers.length-1;i++)
{
for(int j=0 ; j<(length-answers[i].length()-i) ; j++)
{
System.out.print(" ");
}
System.out.println(answers[i]);
}
for(int i=0 ; i<answers[answers.length-1].length(); i++)
{
System.out.print("-");
}
System.out.println();
System.out.println(answers[answers.length-1]);
}
}
發佈完整的異常堆棧跟蹤。 – Unihedron
爲什麼不自己運行它並使用堆棧跟蹤來查找錯誤？沒有什麼比這更容易。 – MightyPork
我的編譯器沒有給出任何異常。它的UVa在線評判告訴我，在我的程序中存在運行時錯誤 – Mujadded