2015-01-09 45 views
4

是否可以在Swift中將每個字符串放入數組中?如何在Swift中將字符串的每個單詞放入數組中?

例如:

var str = "Hello, Playground!" 

到:

var arr = ["Hello","Playground"] 

謝謝:)

+2

相關[夫特:分割字符串到一個數組(http://stackoverflow.com/questions/25678373/swift -split-A-串 - 進入 - 一個陣列) – 2015-01-09 22:38:40

回答

6

編輯/更新:

斯威夫特3.X

extension String { 
    var wordList: [String] { 
     return components(separatedBy: .punctuationCharacters) 
      .joined() 
      .components(separatedBy: .whitespaces) 
    } 
} 

SWIFT 2.1

​​
let myWordList = "Hello, Playground!".wordList // ["Hello", "Playground"] 
0

這最後溶液(來自LEO)將創建陣列中空元素當存在字符串中多個連續的空格。它還會合並用「 - 」分隔的單詞並將行尾字符處理爲單詞。

這一個不會:

extension String 
{  
    var wordList: [String] 
    { 
     return componentsSeparatedByCharactersInSet(NSCharacterSet.alphanumericCharacterSet().invertedSet).filter({$0 != ""}) 
    } 
} 
0

兩個答案目前與斯威夫特4,但下列可以覆蓋OP的問題&希望你的。

extension String { 
    var wordList: [String] { 
     return components(separatedBy: CharacterSet.alphanumerics.inverted).filter { !$0.isEmpty } 
    } 
} 

let string = "Hello, Playground!" 
let stringArray = string.wordList 
print(stringArray) // ["Hello", "Playground"] 

而且隨着用數字和一個雙空間更長的短語:

let biggerString = "Hello, Playground! This is a very long sentence with 123 and other stuff in it" 
let biggerStringArray = biggerString.wordList 
print(biggerStringArray) 
// ["Hello", "Playground", "This", "is", "a", "very", "long", "sentence", "with", "123", "and", "other", "stuff", "in", "it"] 
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