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我正在嘗試使用模式添加記錄。我已經使用下面的代碼，但我的記錄不會被添加到數據庫中..幫我通過請使用Ajax將記錄插入到mysql數據庫中
<link rel="stylesheet" type="text/css" href="/Project/Style/bootstrap.css"/>
<script src="Style/jQuery/jquery-1.11.1.min.js" type="text/javascript"></script>
</head>
<body>
<div id="container">
<?php
include('header.php');
require_once('Connections/conn.php');
$sql2= "SELECT * from type where cid='1' ";
$results =mysqli_query($conn,$sql2);
?>
<div id="main">
<div class="container" >
<div class="row">
<div class="form-group col-md-3">
<button type="button" class="btn btn-primary" data-toggle="modal" data-target="#myModal">
++Add Farm Product
</button>
</div>
<div class="input-group col-md-4 col-sm-offset-2">
<span class="input-group-addon">Search</span>
<input type="text" class="form-control" name="search-text" id="search-text" placeholder="Search By Product Name">
</div>
</div>
<div id="result"></div>
<!-- Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel">Add Farm Product</h4>
</div>
<div class="modal-body">
<form>
<div class="row">
<div class="col-md-6 padding-top-10">
<label for="proname" class="control-label">Product Name:</label>
<input type="text" class="form-control" id="proname" placeholder="Product Name" name="proname" />
</div>
<div class="col-md-5 padding-top-10">
<label for="pro-type" class="control-label">Product Type:</label>
<select class="form-control" id="pro_type" name="pro_type" >
<option>Select Product type...</option>
<?php foreach($results as $result): ?>
<option value= " <?php echo $result['tid']; ?>" > <?php echo $result['type_name']; ?>
</option>
<?php endforeach ;?>
</select>
</div>
</div><br/>
<div class="row">
<div class="col-md-4 padding-top-10">
<label for="qty" class="control-label">Quantity:</label>
<input type="text" class="form-control" id="qty" placeholder="Quantity" name="qty" />
</div>
<div class="col-md-4 padding-top-10">
<label for="price" class="control-label">Unit Price :</label>
<input type="text" class="form-control" id="price" placeholder="Unit Price" name="price" />
</div>
<div class="col-md-4 padding-top-10">
<label for="pdate" class="control-label"> Production Date :</label>
<input type="date" class="form-control" id="pdate" placeholder="Production Date" name="pdate" />
</div>
</div>
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal" >Close</button>
<button type="button" id="add" name="add" class="btn btn-primary">Add Product</button>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</body>
</html>
<script>
// haddling the post for adding record
$('#add').click(function(){
var proname = $('#proname').val();
var pro_type = $('#pro_type').val();
var qty = $('#qty').val();
var price = $('#price').val();
var pdate = $('#pdate').val();
var datas="proname="+proname+"&pro_type="+pro_type+"&qty="+qty+"&price="+price+"&pdate"+pdate;
$.ajax({
type: "POST",
url: "addpro_exec.php",
data: datas,
success:function(data){
},
error: function(){
}
});
});
</script>
代碼處理髮布的數據如下 //addpro_exec.php文件
<?php
require_once('Connections/conn.php');
if(isset($_POST['add'])){
$proname=$_POST['proname'];
$pro_type= $_POST['pro_type'];
//$typname=$_POST['type_name'];
$qty= $_POST['qty'];
$price= $_POST['price'];
$pdate= $_POST['pdate'];
$asdate = \date('F');
$sql="INSERT into product VALUES('','$proname','','$qty','$price','$pdate','','$pro_type','1') ON DUPLICATE KEY UPDATE qty = qty+$qty";
$sql2= "INSERT into year_estm VALUES('','$proname','$asdate','$qty','') ON DUPLICATE KEY update Production_input=Production_input+$qty ";
$AddProduction= mysqli_query($conn, $sql2) or die('Cannot add to production'. mysqli_error($conn));
$RecAdd= mysqli_query($conn,$sql) or die('Cannot add Product' . mysqli_error());
if($RecAdd){
header('location:viewfarm.php');
}
}
else{
}
?>
這很難回答，因爲您沒有顯示您嘗試調試的內容。有沒有錯誤？你知道AJAX調用是否有效嗎？你有沒有檢查你的控制檯？如果你不使用AJAX直接發佈到url addpro_exec.php會發生什麼呢？它會工作嗎？ –
看看這一行，'if（isset（$ _ POST ['add']））{...'。 '$ _POST ['add']'沒有設置，那是因爲你沒有在你的AJAX請求中發送任何東西。此外，缺少'='在這裏，'...「＆pdate」+ pdate;' –
沒有ajax，它工作得很好，..我第一次學習ajax @cale_b – Othman