所有表如果我運行下面的腳本生成創建表腳本(使用索引,鍵約束),在SQL Server數據庫
SELECT so.Name, sc.Text
FROM syscomments sc JOIN sysobjects so ON sc.ID = so.ID
我會得到所有的創造過程/函數的腳本。對於表,索引,鍵和觸發器有沒有這樣的事情?
謝謝你的幫助!
所有表如果我運行下面的腳本生成創建表腳本(使用索引,鍵約束),在SQL Server數據庫
SELECT so.Name, sc.Text
FROM syscomments sc JOIN sysobjects so ON sc.ID = so.ID
我會得到所有的創造過程/函數的腳本。對於表,索引,鍵和觸發器有沒有這樣的事情?
謝謝你的幫助!
沒有內置。
在T-SQL中執行此操作您需要查找或編寫自己的腳本。 Example here可能會讓你開始。
for SQL 2012 and later use this
我已經嘗試了很多web腳本。他們都有缺陷。我終於在msdn網站上使用了一篇文章編寫了腳本,並將其改爲適用於許多情況。
注意:此腳本的工作原理的SQL Server 2012和更高版本的
WITH IndexInfo AS (
SELECT ix.object_id
, ix.NAME AS IndexName
, ix.type_desc
, ix.filter_definition
, ix.is_unique
, ix.is_primary_key
, ix.allow_row_locks
, ix.allow_page_locks
, ds.NAME AS DataSpaceName
, ds.type AS DataSpaceType
, ix.is_padded
, object_schema_name(ix.object_id) AS SchemaName
, object_name(ix.object_id) AS TableName
, IIF(ix.type <= 2, is_included_column, 0) AS HasIncludedColumn
, IIF(ix.type in (5, 6), 1, 0) AS IsColumnStore
, (
SELECT KeyColumns
FROM (
SELECT IC2.object_id
, IC2.index_id
, STUFF((
SELECT ' , ' + C.NAME + IIF(MAX(CONVERT(INT, IC1.is_descending_key)) = 1 AND ix.type <= 2, ' DESC ', ' ')
FROM sys.index_columns IC1
JOIN sys.columns C ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
--AND IC1.is_included_column = 0
AND IIF(ix.type <= 2, IC1.is_included_column, 0) = 0
AND IIF(ix.type <= 2, IC1.key_ordinal, ic.index_column_id) > 0
WHERE IC1.object_id = IC2.object_id
AND IC1.index_id = IC2.index_id
GROUP BY IC1.object_id
, C.NAME
, index_id
, IC1.key_ordinal
, IC1.index_column_id
ORDER BY IIF(ix.type <= 2, IC1.key_ordinal, IC1.index_column_id)
FOR XML PATH('')
), 1, 2, '') KeyColumns
FROM sys.index_columns IC2
GROUP BY IC2.object_id
, IC2.index_id
) tmp
WHERE tmp.object_id = ix.object_id
AND tmp.index_id = ix.index_id
) AS KeyColumnsStr
, (
SELECT IncludedColumns
FROM (
SELECT IC2.object_id, IC2.index_id
, STUFF((
SELECT ' , ' + C.NAME
FROM sys.index_columns IC1
JOIN sys.columns C ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
--AND IC1.is_included_column = 1
AND IIF(ix.type <= 2, IC1.is_included_column, 0) <> 0
WHERE IC1.object_id = IC2.object_id
AND IC1.index_id = IC2.index_id
--and IIF(ix.type <= 2, IC1.key_ordinal, ic.index_column_id) > 0
GROUP BY IC1.object_id, C.NAME, index_id, IC1.key_ordinal, IC1.index_column_id
ORDER BY IIF(ix.type <= 2, IC1.key_ordinal, IC1.index_column_id)
FOR XML PATH('')
), 1, 2, '') IncludedColumns
FROM sys.index_columns IC2
GROUP BY IC2.object_id, IC2.index_id
) tmp
WHERE tmp.object_id = ix.object_id
AND tmp.index_id = ix.index_id
AND IncludedColumns IS NOT NULL
) AS IncludedColumnsStr
FROM sys.indexes ix
INNER JOIN sys.index_columns ic ON ic.index_id = ix.index_id AND ic.object_id = ix.object_id
INNER JOIN sys.columns col ON col.column_id = ic.column_id AND col.object_id = ix.object_id
INNER JOIN sys.data_spaces ds ON ix.data_space_id = ds.data_space_id
WHERE ix.NAME IS NOT NULL AND IIF(ix.type <= 2, ic.key_ordinal, ic.index_column_id) > 0
)
, Scrpt AS (
SELECT *
, 'CREATE '
+ CASE WHEN is_unique = 1 THEN ' UNIQUE ' ELSE '' END
+ type_desc COLLATE DATABASE_DEFAULT + ' INDEX ' + IndexName + ' ON '
+ SchemaName + '.' + TableName + '(' + KeyColumnsStr + ')'
+ ISNULL(IIF(HasIncludedColumn > 0, ' ', ' INCLUDE (' + IncludedColumnsStr + ')'), '')
+ IIF(filter_definition IS NULL, ' ', ' WHERE ' + filter_definition)
+ ' WITH ('
+ CASE WHEN IsColumnStore = 1 THEN ' DROP_EXISTING = OFF '
ELSE
IIF(is_padded = 1, ' PAD_INDEX = ON ', ' PAD_INDEX = OFF ') + ','
+ ' DROP_EXISTING = OFF ' + ','
+ ' ONLINE = OFF ' + ','
+ IIF(allow_row_locks = 1, ' ALLOW_ROW_LOCKS = ON ', ' ALLOW_ROW_LOCKS = OFF ') + ','
+ IIF(allow_page_locks = 1, ' ALLOW_PAGE_LOCKS = ON ', ' ALLOW_PAGE_LOCKS = OFF ')
END
+ ') '
+ IIF(DataSpaceType = 'FG','ON [' + DataSpaceName + ']', '') AS CreateIndexScript
FROM IndexInfo
)
SELECT DISTINCT IndexName, CreateIndexScript
FROM Scrpt
WHERE object_id = object_id('dbo.SWPartition')
作爲信貸原作者,我提到了原來的鏈接在這裏 How to Generate Index Creation Scripts
的[可能的複製生成所有指標的劇本,在SQL Server數據庫中的鍵](http://stackoverflow.com/questions/18610288/generate-script-of-all-indexes-keys-in-the-sql-server-database) – bummi 2015-12-17 23:27:17