PHPMailer沒有發送，沒有給出錯誤拋出500錯誤

Question

更新：這是我收到的錯誤：SMTP連接（）失敗。 致命錯誤：未收到異常'phpmailerException'，並顯示消息'SMTP連接（）失敗。'

我正在使用一個名爲Frameworx的預先存在的php框架。一切都很好，但它不會發送我認爲是的電子郵件，因爲我使用的是OpenShift，而且他們對郵件服務器嚴格。我需要使用SendGrid，所以我試圖使用PHPMailer來做到這一點。也許我正在談論這一切都是錯誤的。但基本上，當我嘗試發送郵件時，我所得到的只是一個空白頁面。用戶已創建。

這是我有：

 // Create a New Account Form 
    if (isset($_POST['submit']) && $_POST['submit'] == 'newAccount') { 
     // User Validations 
     if($_POST['usersName'] == '') { 
      $msgBox = alertBox("Your First and Last Name is required.", "<i class='fa fa-times-circle'></i>", "danger"); 
     } else if($_POST['usersEmail'] == '') { 
      $msgBox = alertBox("A valid Email Address is required.", "<i class='fa fa-times-circle'></i>", "danger"); 
     } else if($_POST['password'] == '') { 
      $msgBox = alertBox("A New Account Password is required.", "<i class='fa fa-times-circle'></i>", "danger"); 
     } else if($_POST['password'] != $_POST['passwordr']) { 
      $msgBox = alertBox("Passwords do not match, please check your entries.", "<i class='fa fa-times-circle'></i>", "danger"); 
     // Black Hole Trap to help reduce bot registrations 
     } else if($_POST['captcha'] != '') { 
      $msgBox = alertBox("An Error was encountered and the New Account could not be created.", "<i class='fa fa-times-circle'></i>", "danger"); 
     } else { 
      // Set some variables 
      $dupEmail = ''; 
      $newEmail = $mysqli->real_escape_string($_POST['usersEmail']); 

      // Check for Duplicate email 
      $check = $mysqli->query("SELECT 'X' FROM users WHERE usersEmail = '".$newEmail."'"); 
      if ($check->num_rows) { 
       $dupEmail = 'true'; 
      } 

      // If duplicates are found 
      if ($dupEmail != '') { 
       $msgBox = alertBox("There is all ready a User Account registered with that Email Address.", "<i class='fa fa-times-circle'></i>", "danger"); 
      } else { 
       // Create the new account 
       $password = encryptIt($_POST['password']); 
       $usersName = $mysqli->real_escape_string($_POST['usersName']); 
       $joinDate = date("Y-m-d H:i:s"); 
       $hash = md5(rand(0,1000)); 
       $isActive = '0'; 

       $stmt = $mysqli->prepare(" 
            INSERT INTO 
             users(
              usersEmail, 
              password, 
              usersName, 
              joinDate, 
              hash, 
              isActive 
             ) VALUES (
              ?, 
              ?, 
              ?, 
              ?, 
              ?, 
              ? 
             )"); 
       $stmt->bind_param('ssssss', 
        $newEmail, 
        $password, 
        $usersName, 
        $joinDate, 
        $hash, 
        $isActive 
       ); 
       $stmt->execute(); 

       // Send out the email in HTML 
       require_once('class.phpmailer.php'); 

       $mail = new PHPMailer(true); 

       $mail->SMTPDebug = 2; 

       //Ask for HTML-friendly debug output 
       $mail->Debugoutput = 'html'; 


       $mail->isSMTP();          // Set mailer to use SMTP 
       $mail->Host = 'https://api.sendgrid.com/'; // Specify main and backup SMTP servers 
       $mail->SMTPAuth = true;        // Enable SMTP authentication 
       $mail->Username = 'looloobs';     // SMTP username 
       $mail->Password = 'passowrd';       // SMTP password 
       $mail->SMTPSecure = 'tls';       // Enable TLS encryption, `ssl` also accepted 
       $mail->Port = 587;         // TCP port to connect to    // TCP port to connect to 

       $mail->From = 'militarypropertyproject@gmail.com'; 
       $mail->FromName = 'Mailer'; 
       $mail->addAddress('laurenrothlisberger@gmail.com', 'Joe User');  // Add a recipient 
       $mail->addReplyTo('info@example.com', 'Information'); 

       $mail->Subject = 'Here is the subject'; 
       $mail->Body = 'This is the HTML message body <b>in bold!</b>'; 
       $mail->AltBody = 'This is the body in plain text for non-HTML mail clients'; 


       if(!$mail->send()) { 
        echo 'Message could not be sent.'; 
        echo 'Mailer Error: ' . $mail->ErrorInfo; 
       } else { 
        echo 'Message has been sent'; 
       } 

       $stmt->close(); 


       // Clear the Form of values 
       $_POST['usersName'] = $_POST['usersEmail'] = $_POST['password'] = $_POST['passwordr'] = $_POST['captcha'] = ''; 
      } 
     } 
    } 

Answer 1

它看起來像你正試圖通過SMTP（在Simple Mail Transfer Protocol）發送，但是，你傳遞在SendGrid的Web API域中作爲主機名。因此，當phpmailer試圖連接到「域」https://api.sendgrid.com/它失敗。

爲了解決這個問題，改變這一行：

$mail->Host = 'https://api.sendgrid.com/'; // Specify main and backup SMTP servers 

要：

$mail->Host = 'smtp.sendgrid.net'; // Specify main and backup SMTP servers 

Answer 2

$mail->IsMail(); 

，你必須使用這個