無法檢索數據庫中的值並且無法更新表

Question

情況： 我有changepass頁面來更改密碼。但頁面無法檢索並顯示數據庫中的值。我想顯示已存儲在數據庫中的ID，名稱和部門。該newpasswword也不能更新... plz..help我..

下面的代碼：

<?php 
    session_start(); 
    $username = $_SESSION["username"]; 

?> 
<?php 
$con = mysql_connect("localhost","root",""); 
if (!$con) 
    { 
    die('Could not connect: ' . mysql_error()); 
    } 

mysql_select_db("fyp", $con); 

    $username=$_SESSION["username"]; 


    $query = "SELECT * from access WHERE username = '$username'"; 
    $result = @mysql_query($query); 
    $row = mysql_fetch_array($result); 
    $username   = $row["username"]; 
    $name    = $row["name"]; 
    $department   = $row["department"]; 

    mysql_query($query) or die ("Query Failed".mysql_error()); 

    //mysql_close($link); 


if(isset($_POST['submit'])) 
{ 
if (!$_POST['newpassword']) 
     { 
      echo "<script language='Javascript'>alert(' Please Enter The New Password');</script>"; 
     } 
    else 
    { 
    $newpassword=$_POST['newpassword']; 
    if(!eregi("^[[:alnum:]]{6,12}$", $newpassword)) 
     { 
      echo "<script language='Javascript'>alert(' New Password must be 6-12 element');</script>"; 
     } 
    else { 
    $query1 = "UPDATE access SET password=$newpassword WHERE username = '$username'"; 
    mysql_query($query1) or die ("Query Failed".mysql_error()); 

    echo "<script> alert('Change Password Success. Please Login With The New Password.'); 
    document.location.href='login.php?mosmsg=Please enter the value'</script>\n"; 
     } 
    } 
} 
?> 

<font face= "arial" size="2" font color="black"> 
<center> 
<h3 align=center> Change Password </h3> 
<table width="500" height="100" border="0" cellspacing="0" cellpadding="2"> 

<tr> 
     <tr> 
      <td align="left">User ID</td> 
      <td>: <? {echo "$username"; } ?></td> 
     </tr> 

     <tr> 
     <td align="left">Name </td> 
     <td>: <? {echo "$name"; } ?></td> 
    </tr>  

     <tr> 
      <td align="left">Department </td> 
      <td>: <?php echo $row['department']; ?> </td>  
     </tr> 

     <tr> 
      <td align="left">New Password </td> 
      <td>: <input name="newpassword" type="password" id="newpassword" size="20" ></td> 
     </tr> 

Answer 1

您正在使用mysql_query函數兩次這是錯誤的，刪除此行：

mysql_query($query) or die ("Query Failed".mysql_error()); 

您的代碼應該是這樣的：

$query = "SELECT * from access WHERE username = '$username'"; 
$result = mysql_query($query) or die(mysql_error()); 
$row = mysql_fetch_array($result); 
$username   = $row["username"]; 
$name    = $row["name"]; 
$department   = $row["department"]; 

這樣你會知道，如果re是mysql中的任何錯誤，如果有錯誤的話，可以繼續執行。讓我們知道這是否工作或有一個MySQL錯誤。

編輯： 幾件事情，首先你缺少你的HTML標籤form，二把這些線在腳本的開始知道你收到了什麼錯誤。

ini_set('display_errors', true); 
error_reporting(0);