的Xquery使用多個搜索領域

我有以下XML的架構一個電影數據庫：的Xquery使用多個搜索領域

<movies> 
    <movie> 
    <title>A History of Violence</title> 
    <year>2005</year> 
    <country>USA</country> 
    <genre>Crime</genre> 
    <summary>Tom Stall, a humble family man and owner of a 
    popular neighborhood restaurant, lives a quiet but 
    fulfilling existence in the Midwest. One night Tom 
    foils a crime at his place of business and, to his 
    chagrin, is plastered all over the news for his 
    heroics. Following this, mysterious people follow 
    the Stalls' every move, concerning Tom more than 
    anyone else. As this situation is confronted, more 
    lurks out over where all these occurrences have 
    stemmed from compromising his marriage, family 
    relationship and the main characters' former 
    relations in the process.</summary> 
<director>  
     <last_name>Cronenberg</last_name> 
     <first_name>David</first_name> 
     <birth_date>1943</birth_date> 
</director> 
<actor> 
     <first_name>Vigo</first_name> 
     <last_name>Mortensen</last_name> 
     <birth_date>1958</birth_date> 
     <role>Tom Stall</role> 
</actor> 
<actor> 
     <first_name>Maria</first_name> 
     <last_name>Bello</last_name> 
     <birth_date>1967</birth_date> 
     <role>Eddie Stall</role> 
</actor> 
<actor> 
     <first_name>Ed</first_name> 
     <last_name>Harris</last_name> 
     <birth_date>1950</birth_date> 
     <role>Carl Fogarty</role> 
</actor> 
<actor> 
     <first_name>William</first_name> 
     <last_name>Hurt</last_name> 
     <birth_date>1950</birth_date> 
     <role>Richie Cusack</role> 
</actor> 
</movie> 
</movies>

我現在創建的搜索字段演員第一/姓氏;類型;國家;年和角色。

但問題是，它只與去年和體裁的作品。

如果我使用

流派或年：我得到正確的結果
姓氏; FIRST_NAME;國家;作用：我得不到結果

我想它與多個演員和多個國家的元素有些待辦事項，但我無法弄清楚如何解決它。

這裏是我的XQuery代碼：

xquery version "3.0"; 
(: :declare namespace util="http://exist-db.org/xquery/util";:) 
declare option exist:serialize "method=xhtml media-type=text/html indent=yes"; 

let $year := lower-case(request:get-parameter('year', '')) 
let $genre := request:get-parameter('genre', '') 
let $first_name := request:get-parameter('first_name', '') 
let $last_name := request:get-parameter('last_name', '') 
let $country := request:get-parameter('country', '') 
let $role := request:get-parameter('role', '') 



let $movies := collection('/db/Movie/data')/movies/movie[if(not($genre)) then xs:boolean(1) else equals(genre, $genre)][if(not($year)) then xs:boolean(1) else equals(year, $year)][if(not($country)) then xs:boolean(1) else equals(//country, $country)][if(not($first_name)) then xs:boolean(1) else equals(//actor/first_name, $first_name)][if(not($last_name)) then xs:boolean(1) else equals(//actor/last_name, $last_name)][if(not($role)) then xs:boolean(1) else equals(//actor/role, $role)] 

return 
<html> 
<head> 

    </head> 
    <body> 
     <h1>Search results:</h1> 

     <ol>{ 
for $movie in $movies 
    let $title := $movie/title/text() 
    let $year := $movie/year/text() 
     return 
       <li>{$title} ({$year})</li> 



     }</ol> 
    </body> 
</html>

提前感謝！電賀

來源

2014-01-11 user3181473

。在你的代碼中的錯字。在last_name的過濾謂詞中，使用變量$ first_name。使用多一點的線端和空白可能會使它更容易發現這樣的錯誤。

您也可以使謂詞有點用一個更聰明的布爾表達式短。您可以更換xs:boolean(1)通過true()，但你也可以重寫謂詞如下：

[empty($genre) or equals(genre, $genre)]

HTH！

來源

2014-01-11 22:05:25 grtjn

謝謝，我糾正了錯字，但它沒有工作:(現在我也得到了last_name沒有結果了 – user3181473

@ user3181473：試圖刪除//國家/地區等//呢？他們是不必要的。他們不應該傷害，我想，但不使用//（幾乎）總是更好.. – grtjn

的Xquery使用多個搜索領域

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