jquery gettting所有匹配的當前html數據

Question

• 在下面的html中，'return_fly26'重複2次。所以我想帶班 'return_fly26' 的 匹配的HTML

---

<div class="col-xs-12 nopadding return_fly26"> 
<div class="col-xs-4 noleftpadding "> 

<div class="col-xs-6 norightpadding movies"> 
<img src="d.gif" alt="App Logo"> 
</div> 
<div class="col-xs-6 flightinformation"> 

<p class="ddd">ssss</p> 
</div> 
</div> 

<div class="col-xs-5 noleftpadding"> 

<p class="timings">ssss</p> 
<p class="stops">01 h : 30 m</p> 
</div> 
</div> 

<div class="col-xs-12 nopadding return_fly26"> 
<div class="col-xs-4 noleftpadding "> 

<div class="col-xs-6 norightpadding movies"> 
<img src="d.gif" alt="App Logo"> 
</div> 
<div class="col-xs-6 flightinformation"> 

<p class="ddd">ssss</p> 
</div> 
</div> 

<div class="col-xs-5 noleftpadding"> 

<p class="timings">ssss</p> 
<p class="stops">01 h : 30 m</p> 
</div> 
</div> 

下面是我怎樣努力

$(".onward_fly").html(""); 
var owner = $('.return_fly'+flight_id).html(); 
console.log(owner); 

如果我安慰它我得到一個一個的div匹配匹配與.return_fly26。任何人都可以建議這個!!!!!!

預期的輸出應該與上面使用jquery相同。

O/P：

---

<div class="col-xs-12 nopadding return_fly26"> 
<div class="col-xs-4 noleftpadding "> 

<div class="col-xs-6 norightpadding movies"> 
<img src="d.gif" alt="App Logo"> 
</div> 
<div class="col-xs-6 flightinformation"> 

<p class="ddd">ssss</p> 
</div> 
</div> 

<div class="col-xs-5 noleftpadding"> 

<p class="timings">ssss</p> 
<p class="stops">01 h : 30 m</p> 
</div> 
</div> 

<div class="col-xs-12 nopadding return_fly26"> 
<div class="col-xs-4 noleftpadding "> 

<div class="col-xs-6 norightpadding movies"> 
<img src="d.gif" alt="App Logo"> 
</div> 
<div class="col-xs-6 flightinformation"> 

<p class="ddd">ssss</p> 
</div> 
</div> 

<div class="col-xs-5 noleftpadding"> 

<p class="timings">ssss</p> 
<p class="stops">01 h : 30 m</p> 
</div> 
</div> 

Answer 1

讀jQuery selectors API。正確的代碼是這樣的：

// gets collection 
var myDivs = $('div.return_fly26');