從塊中的變量被放入計算中，但拋出錯誤的讀數

Question

我有麻煩試圖檢索一個已經在塊外部建立並調用內部的雙變量，但我想返回相同變量的值，以便我可以將其應用於計算。

，我想返回的變量是：

double quarter = 0; 

但是當我將其插入季度我第一個else/if語句，它插入在0，而不是在我的開關塊的價值。我能做些什麼來檢索價值？

 double quarter = 0; 

     //Date entry will be calculated by how much KW user enters 
     switch (input) 
     { 
      case "2/15/13": 
       quarter = kwUsed * 0.10; 
       break; 
      case "4/15/13": 
       quarter = kwUsed * 0.12; 
       break; 
      case "8/15/13": 
       quarter = kwUsed * 0.15; 
       break; 
      case "11/15/13": 
       quarter = kwUsed * 0.15; 
       break; 
      default: 
       System.out.println("Invalid date"); 
     } 


     //Declaring variables for calculations 
     double base = 0; 
     double over = 0; 
     double excess = 0; 

     double math1 = 0; 
     double math2 = 0; 


     //KW Calculations 
     if (kwUsed <= 350) 
     { 
      base = quarter; 

     }else if (kwUsed <= 500) 
     { 
      math1 = ((kwUsed - 350) * quarter); 
      base = ((kwUsed * quarter) - math1); 
      over = ((math1 * 0.1) + math1); 

     }else if (kwUsed > 500) 
     { 
      math2 = ((kwUsed - 350) * 0.1); 
      base = ((kwUsed * 0.1) - math2); 
      math2 = ((kwUsed -350) - 50); 
      over = ((math2 * 0.1) + (15 * 0.1)); 
      double math3 =((kwUsed - 500) * 0.1); 
      excess = ((math3 * 0.25) + math3); 

     } 

編輯澄清問題。

Answer 1

它必須是kwUsed = 0在switch或輸入的日期是錯誤的。如果這些值是正確的，則quarter不能爲零。

double price = 0; 
switch (input) 
    { 
     case "2/15/13": 
      price = 0.10; 
      break; 
     case "4/15/13": 
      price = 0.12; 
      break; 
     case "8/15/13": 
      price = 0.15; 
      break; 
     case "11/15/13": 
      price = 0.15; 
      break; 
     default: 
      System.out.println("Invalid date"); 
    } 


    //Declaring variables for calculations 
    double base = 0; 
    double over = 0; 
    double excess = 0; 

    double math1 = 0; 
    double math2 = 0; 


    //KW Calculations 
    if (kwUsed <= 350) 
    { 
     base = kwUsed * price; 

    }else if (kwUsed <= 500) 
    { 
     math1 = ((kwUsed - 350) * price); 
     base = ((kwUsed * price) - math1); 
     over = ((math1 * 0.1) + math1); 

    }...