如何通過文件夾更改文件名？

Question

我有大約1000文件的文件夾是這樣的：

$ awk '{print $9}' folder 
1003ns_cells_found.fcs 
1003pi_cells_found.fcs 
1007ns_cells_found.fcs 
1007pi_cells_found.fcs 
1029ns_cells_found.fcs 
1029pi_cells_found.fcs 
1041nsA_cells_found.fcs 

而且我還有一個ID文件是這樣的：

$ head -5 ID 
1003 BD2188 
1003 BD2188 
1007 BD2116 
1007 BD2116 
1029 BD2012 

我會與替換文件夾中的所有文件的ID號ID文件的第二列。有誰知道如何通過Terminal/Shell實現它？

Answer 1

這個簡單的腳本應該這樣做：

#!/bin/bash 

ls ./folder | while read line; do 
cat ID | awk -v x=${line:0:4} 'x==$1 {printf "%s", $2; exit}' 
echo -e "${line:4}"; 
done 

的文件夾結構如下所示：

$ find 
. 
./ID <-- file with the IDs 
./folder 
./folder/1003pi_cells_found.fcs 
./folder/1041nsA_cells_found.fcs 
./folder/1007pi_cells_found.fcs 
./folder/1007ns_cells_found.fcs 
./folder/1029pi_cells_found.fcs 
./folder/1003ns_cells_found.fcs 
./folder/1029ns_cells_found.fcs 
./script <-- script to execute 

輸出：

BD2188ns_cells_found.fcs 
BD2188pi_cells_found.fcs 
BD2116ns_cells_found.fcs 
BD2116pi_cells_found.fcs 
BD2012ns_cells_found.fcs 
BD2012pi_cells_found.fcs 
nsA_cells_found.fcs 

最後一個是空的，因爲1041沒有找到在文件ID。