爲什麼JsonConvert.DeserializeObject不起作用？

我從web服務的結果，該字符串結果是：爲什麼JsonConvert.DeserializeObject不起作用？

{"status":"success","data":{"address":"[email protected]","unconfirmed":[{"tx":"cb2f252078d933f63d9cef52bee8857427d70c1142f41f10567cfad7ef1d2dcb","time_utc":"2015-03-31T19:05:09Z","amount":0.1,"n":0},{"tx":"a34fc5b8b3c29c7046ca8acaedd39280f81597a853f30825856e2f46e498c478","time_utc":"2015-03-31T19:05:01Z","amount":0.1,"n":0}]},"code":200,"message":""}

我打電話JsonConvert.DeserializeObject：

UTByAddressessResponse數據= Serializer.Deserialize（結果）;

public static T Deserialize<T>(string json) 
     { 
      return JsonConvert.DeserializeObject<T>(json); 
     } 




public class UTByAddressessResponse 
    { 
     public string status { get; set; } 
     public UnconfirmedAddressInfo[] data { get; set; } 

     public string code { get; set; } 
     public string message { get; set; } 
    } 


public class UnconfirmedAddressInfo 
    { 
     public string address { get; set; } 
     public List<UT> unconfirmed { get; set; } 
    } 



public class UT 
    { 
     public string tx { get; set; } 
     public DateTime time_utc { get; set; } 
     public float amount { get; set; } 
     public long n { get; set; } 
    }

但是要得到一個錯誤：

無法反序列化當前JSON對象（例如{ 「名稱」：「值」}）成型「Dice.Common.Objects.UnconfirmedAddressInfo [] '因爲類型需要JSON數組（例如[1,2,3]）才能正確地反序列化。

爲什麼？

來源

2015-03-31 Haddar Macdasi

的問題是，

public class UTByAddressessResponse 
    { 
     public string status { get; set; } 
     public UnconfirmedAddressInfo[] data { get; set; } 

     public string code { get; set; } 
     public string message { get; set; } 
    }

應該

public class UTByAddressessResponse 
    { 
     public string status { get; set; } 
     public UnconfirmedAddressInfo data { get; set; } // not array 

     public string code { get; set; } 
     public string message { get; set; } 
    }

來源

2015-03-31 20:30:02

您的JSON粘貼到http://json2csharp.com/這將創建下列類別

public class Unconfirmed 
{ 
    public string tx { get; set; } 
    public string time_utc { get; set; } 
    public double amount { get; set; } 
    public int n { get; set; } 
} 

public class Data 
{ 
    public string address { get; set; } 
    public List<Unconfirmed> unconfirmed { get; set; } 
} 

public class RootObject 
{ 
    public string status { get; set; } 
    public Data data { get; set; } 
    public int code { get; set; } 
    public string message { get; set; } 
}

現在你可以反序列化作爲

var obj = JsonConvert.DeserializeObject<RootObject>(json_string);

PS：你可以爲你的類名，但如果要重命名的屬性，您應該使用JsonProperty屬性。

來源

2015-03-31 19:40:31 EZI

爲什麼JsonConvert.DeserializeObject不起作用？

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