密碼驗證始終返回false。我在這裏看到了每個答案,但沒有一個幫助。密碼字段是varchar(255)。當我從數據庫var_dump密碼時,它顯示字符串(60)並且密碼正確,但該函數仍然返回false。 下面是存儲在數據庫中的代碼:password_verify始終返回false,並且我無法在任何地方找到答案
if(empty($_POST['pass'])) {
$passErr = "Password required!";
$errors[] = "Pass error";
} else {
$pass = test_input($_POST["pass"]);
if(!preg_match("/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$/", $pass)) {
$passErr = "Password not well formed";
$errors[] = "Pass error";
} else {
$pass_hashed = password_hash($pass, PASSWORD_DEFAULT);
}
}
$hash_ver = md5(rand(0, 1000));
$status = "";
$stm = $conn->prepare("INSERT INTO user VALUES(?, ?, ?, ?, ?, ?, ?, ?)");
$stm->bind_param("sssssssi", $id, $pass_hashed, $email, $fName, $lName, $hash_ver, $status, $id_role);
$stm->execute();
echo strlen($pass_hashed);
這是登錄腳本的一部分
if(count($array) != 0) {
echo "<script>alert('Ima gresaka')</script>";
} else {
include('connectionFile/connection.php');
$stmt = $conn->prepare("SELECT `name`,`last_name`,`status_verif`,`email`,`password` FROM user WHERE `email`=?");
$stmt->bind_param("s", $email);
$stmt->execute();
if($res = $stmt->get_result()) {
$count = $res->num_rows;
if($count == 1) {
$row = $res->fetch_assoc();
$passwordb = $row['password'];
//echo "<p>".$passwordb."</p>";
$verify = password_verify($pass, $passwordb);
if($verify) {
echo "<script>alert('Password match')</script>";
} else {
var_dump($verify);
var_dump($passwordb);
echo "<script>alert('Password doesnt match')</script>";
}
} else {
echo "<script>alert('0 rows')</script>";
}
} else {
echo "<script>alert('No rows at all')</script>";
}
}
你試過迴應你的'$ pass'嗎?它是否按預期得到了印刷品? –
這個方法做了什麼'test_input()'?也許它是添加/嵌入你不知道的東西。 –
你也不應該以任何方式操縱密碼,並可能是所有這些的原因。 –