如何獲取表獅身人面像的名字？

Question

我使用PHP斯芬克斯客戶端（PECL）：

$s = new SphinxClient; $s->setServer("localhost", 9312); 
$s->setMaxQueryTime(9000); 
$s->setMatchMode(SPH_MATCH_ANY); 

$result = $s->query($_POST['search'], '*'); 
var_dump($result); 

請求後我得到一個輸出數組：

["fields"]=> 
    array(4) { 
    [0]=> 
    string(4) "type" 
    [1]=> 
    string(18) "specializationname" 
    [2]=> 
    string(17) "detailtousersname" 
    [3]=> 
    string(18) "detailtousersphoto" 
    } 

在輸出陣列我試圖讓表，其中發現數據的名稱（ ID的）。此設置我定在sphinx.conf中：

sql_query = SELECT idArticle as id, 'article' as type... 
sql_field_string = type 

如何，我可以得到一個表名'article'？

源配置例如：

source users : lsParentSource 
{ 

    sql_query_range = SELECT MIN(idDetailToUsers), MAX(idDetailToUsers) FROM detailtousers 
    sql_range_step = 128 
    sql_query   = SELECT idDetailToUsers as id, 9 as type, UsersTypeAccount, idDetailToUsers, SpecializationName, DetailToUsersName, DetailToUsersPhoto, city, country FROM detailtousers join users ON users.idUsers = detailtousers.idDetailToUsers left join usersspecialization ON usersspecialization.UsersSpecializationIdUser = detailtousers.idDetailToUsers left join specializationtousers ON specializationtousers.idSpecialization = usersspecialization.UsersSpecializationIdSpecialization WHERE idDetailToUsers >= $start AND idDetailToUsers <= $end GROUP BY idDetailToUsers 

    sql_attr_uint  = type 
    sql_attr_uint  = idDetailToUsers 
    sql_attr_uint  = UsersTypeAccount 
    sql_field_string = SpecializationName 
    sql_field_string = DetailToUsersName 
    sql_field_string = DetailToUsersPhoto 
    sql_attr_uint  = city 
    sql_attr_uint  = country 

    sql_query_info = SELECT idDetailToUsers, DetailToUsersName, UsersTypeAccount, SpecializationName, DetailToUsersPhoto, city, country \ 
         FROM detailtousers WHERE idDetailToUsers = $id 
    sql_ranged_throttle = 0 
} 

Answer 1

結果數組應該包含匹配陣列（每個文檔的一個）在一個「ATTRS」陣列。