2011-12-02 57 views

回答

1

你可以簡單地使用jQuery的AJAX函數發送到服務器的請求,並聽取了錯誤(即:超時)

var request = $.ajax({ 
    url: "http://somewebsite.com", 
    type: "POST" 
}); 

request.done(function(msg) { 
    $("#log").html("Website is up."); 
}); 

request.fail(function(jqXHR, status) { 
    $("#log").html("Website is down."); 
});