我在使用JAXB從XSD創建XML文件時遇到問題,下面是用於創建它的XSD文件。 (注:名稱已經被編輯過,由於保密)從JAXB的XSD創建XML文件
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" targetNamespace="http://ibm.org/seleniumframework" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="Test" type="sel:Test">
<xs:complexType>
<xs:choice minOccurs="1" maxOccurs="unbounded">
<xs:element name="Option1" type="sel:Option1Type" xmlns:sel="http://ibm.org/seleniumframework"/>
<xs:element name="Option2" type="sel:Option2Type" xmlns:sel="http://ibm.org/seleniumframework"/>
<xs:element name="Option3" type="sel:ScreensType" xmlns:sel="http://ibm.org/seleniumframework"/>
</xs:choice>
</xs:complexType>
</xs:element>
<xs:complexType name="ScreensType">
<xs:sequence>
<xs:element type="sel:ScreenType" name="Screen" minOccurs="1" maxOccurs="unbounded" xmlns:sel="http://ibm.org/seleniumframework"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="ScreenType">
<xs:sequence>
<xs:element name="ScreenData" minOccurs="1" maxOccurs="unbounded" xmlns:sel="http://ibm.org/seleniumframework"/>
</xs:sequence>
<xs:attribute type="xs:string" name="name1" use="required" />
<xs:attribute type="xs:string" name="name2" use="required" />
<xs:attribute type="xs:string" name="name3" use="required" />
</xs:complexType>
</xs:schema>
這是我使用的嘗試和創建XML代碼:
public void generateXml() throws JAXBException, IOException {
Test test = new Test();
ScreensType screens = new ScreensType();
ScreenType screen = new ScreenType();
screen.setName1("a");
screen.setName2("b");
screen.setName3("c");
File f = new File("new.xml");
JAXBContext context= JAXBContext.newInstance("com.q1labs.qa.xmlgenerator.model.generatedxmlclasses");
Marshaller jaxbMarshaller = context.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(test, f);
jaxbMarshaller.marshal(test, System.out);
}
這是輸出
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Test xmlns="http://ibm.org/seleniumframework"/>
我怎樣才能讓代碼輸出屏幕和屏幕標記以及它的屬性,我不知道我在做什麼錯誤。
根據你的代碼,你幾乎不會創建'screen'和'screens'變量,也不會對它們做任何事情。你只是測試。你忘了'test.setOption3(屏幕)'或類似的東西? –