如何讓用戶在python的passowrd程序中退出程序

Question

有人可以試着幫我做這個，請。因此，一旦用戶猜測3次，整個程序關閉，但一旦用戶出錯，它不會讓他們退出程序。是的，我知道我再次問同樣的問題，但我還沒有得到我的問題，所以請有人幫忙。

這裏有另外一個我想出去。任何有關如何通過嘗試猜錯密碼來嘗試退出程序的建議。我一直在嘗試使用sys.exit和exit（），但它並沒有爲我工作，所以也許你可以嘗試一下，（但是請記住我的老師需要它，以便它在IDLE）。

Counter=1 
Password=("Test") 
Password=input("Enter Password: ") 
if Password == "Test": 
    print("Successful Login") 
    while Password != "Test": 
     Password=input("Enter Password: ") 
     Counter=Counter+1 
     if Counter == 3: 
      print("Locked Out: ") 
break 

Answer 1

counter = 1 
password = input("Enter password: ") 
while True: 
    if counter == 3: 
     print("Locked out") 
     exit() 
    elif password == "Test": 
     print("That is the correct password!") 
     break 
    else: 
     password = input("Wrong password, try again: ") 
    counter += 1 

Answer 2

你需要移動while循環

這裏面的條件counter==3也可以通過這種方式

import sys 
password = input("Enter password : ") 
for __ in range(2):  # loop thrice 
    if (password=="Test"): 
     break   #user has enterd correct password so break 
    password = input("Incorrect, try again : ") 
else: 
    print ("Locked out") 
    sys.exit(1) 

#You can put your normal code that is supposed to be 
# executed after the correct password is entered 
print ("Correct password is entered :)") 
#Do whatever you want here 

一個更好的方法是將包裝這個密碼 - 完成把東西檢查成功能。

import sys 
def checkPassword(): 
    password = input("Enter password : ") 
    for __ in range(2): 
     if (password=="Test"): 
      return True 
     password = input("Incorrect, try again : ") 
    else: 
     print ("Locked out") 
     return False 

if (checkPassword()): 
    #continue doing you main thing 
    print ("Correct password entered successfully") 

Answer 3

將您的計數器檢查移入while循環。

還可以使用getpass用於獲取密碼輸入在Python :)

import sys 
import getpass 

counter = 1 
password = getpass.getpass("Enter Password: ") 
while password != "Test": 
    counter = counter + 1 
    password = getpass.getpass("Incorrect, try again: ") 
    if counter == 3: 
    print("Locked Out") 
    sys.exit(1) 
print("Logged on!")