2010-12-07 74 views
0

在我的應用程序我m顯示列表中的Tabview,在一個選項卡時,我試圖啓動一個新的活動onclick列表視圖觸摸事件。我想在網頁視圖中開始一項新活動。錯誤開始新的活動

showNewsListView.setAdapter(listAdapter); 
showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 
      Intent myIntent = new Intent(BizTab.this, MainView.class); 
      startActivity(myIntent); 

      } 
      }); 

getUrlData(baseUrl); 

} 

,如果我跑這麼多的代碼的應用程序崩潰,所以我剛剛找到自己的解決方案,我應該在asyncrouniously開始一個新的活動所以現在即時通訊做這個

showNewsListView.setAdapter(listAdapter); 
    showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView arg0, View arg1, int position, long arg3) { Log.v("status ","tab on position"+position); 

     new ShowFullNews().execute(); 
     } 
     }); 
getUrlData(baseUrl); 

}` 

`showNewsListView.setAdapter(listAdapter); 
showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 

     new ShowFullNews().execute(); 
     } 
     }); 
getUrlData(baseUrl); 

}` 

然後還我的代碼崩潰和不給錯誤只是給這兩個警告

如果我在兩個地方開始一個新的活動onTouch和後執行然後我的代碼是woking,但在這裏它首先顯示屏幕,然後它自動去刷新屏幕,這不看起來不錯。所以如何避免它。請幫我和plese忽略語法錯誤我的工作代碼是

public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 

      //set bundle to send data into other activity 
      b.putInt("total", 10); 
      b.putInt("position",position); 
      b.putStringArray("allurls", allsNewsUrls); 
      b.putString("returnname", "BizTab"); 
      b.putString("footertext","Biz"); 
      b.putInt("tabid", 3); 

      Intent myIntent = new Intent(BizTab.this, MainView.class); 
      myIntent.putExtras(b); 
      startActivity(myIntent); 
      new ShowFullNews().execute(); 
     } 
     }); 

protected void onPostExecute(Long result) { try { 
    Intent myIntent2 = new Intent(BizTab.this, MainView.class); 

startActivity(myIntent2); 


} catch (Exception e) { 
Log.v("error","error in starting new activity"); 
e.printStackTrace(); 
} 

    }` 

日誌生成和我的應用程序正在自動關閉。

12-07 11:55:18.684: WARN/InputManagerService(72): Window already focused, ignoring focus gain of: [email protected] 
12-07 11:55:20.792: VERBOSE/status(419): tab on position0 
12-07 11:55:20.814: INFO/ActivityManager(72): Starting activity: Intent { cmp=org.nuvus/.MainView (has extras) } 
12-07 11:55:20.872: DEBUG/PhoneWindow(419): couldn't save which view has focus because the focused view [email protected] has no id. 
12-07 11:55:21.023: VERBOSE/status(419): mainView oncreate called 
12-07 11:55:21.452: VERBOSE/status(419): onStartcalled 
12-07 11:55:21.962: INFO/ActivityManager(72): Displayed activity org.nuvus/.MainView: 1072 ms (total 1072 ms) 
12-07 11:55:22.082: INFO/AndroidRuntime(419): AndroidRuntime onExit calling exit(0) 
12-07 11:55:22.173: INFO/ActivityManager(72): Process org.nuvus (pid 419) has died. 
12-07 11:55:22.183: INFO/WindowManager(72): WIN DEATH: Window{43fe6f30 org.nuvus/org.nuvus.Main paused=true} 
12-07 11:55:22.202: INFO/WindowManager(72): WIN DEATH: Window{440f9620 org.nuvus/org.nuvus.MainView paused=false} 
12-07 11:55:22.283: INFO/UsageStats(72): Unexpected resume of com.android.launcher while already resumed in org.nuvus 
12-07 11:55:22.303: WARN/InputManagerService(72): Got RemoteException sending setActive(false) notification to pid 419 uid 10032 

請幫我...

+0

你有沒有解決這個問題? – coder 2011-11-29 16:46:20

回答

2

相反的:

Intent myIntent = new Intent(BizTab.this, MainView.class); 
myIntent.putExtras(b); 
startActivity(myIntent); 

嘗試用:

Intent myIntent = new Intent(getBaseContext(), BizTab.this); <!-- or MainView.class--> 
myIntent.putExtras(b); 
myIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); 
startActivity(myIntent); 
+0

仍然是同樣的問題 – neeraj 2010-12-08 06:03:06