在我的循環,我有這樣的如何在node.js中循環工作?
****variable i value****
groupid 0 199
groupid 1 200
groupid 2 201
一組ID,但在循環的總是組201在第一次迭代爲什麼這個happend。這是我的代碼。
for (var i = 0; i < groupdata.length; i++) {
console.log('groupid', i, groupdata[i].id);
var groupname = groupdata[i].name;
var groupid = groupdata[i].id;
var groupType = groupdata[i].groupType;
var getuserdata = {
"groupID": groupdata[i].id,
"groupType": groupdata[i].groupType,
"token": req.usersession.token
};
var digest = BASE.utils.hmac("sha1", "A12AA418-1F28-4464-8B67-29CBD02BC45C-F048B14F-F3E3-4F97-A522-F2275A364A0E", JSON.stringify(getuserdata));
var postData = {
"groupID": groupdata[i].id,
"groupType": groupdata[i].groupType,
"digest": digest,
"token": req.usersession.token
};
var groupUserData = BASE.utils.base64encode(BASE.utils.base64encode(JSON.stringify(postData)));
BASE.request({
url: "http://example.com/getGroupUsers/",
method: "POST",
headers: {
"content-type": "application/json",
},
body: groupUserData
},
function(err, result, groupUserdata) {
var groupuserdata = JSON.parse(groupUserdata);
console.log('first groupusers.....', i, groupuserdata);
var groupids = groupuserdata.groupUsers.filter(function(group) {
if (group.userID != contactid) {
userbody.groups.map(function(usr) {
if (usr.id == groupid) {
console.log('maingroupid....', usr.id);
console.log('current loop groupid..', groupid);
group.groupData = usr;
}
return usr;
})
return group;
}
});
//console.log(groupids);
newgroupdta.push(groupids);
//res.send(groupids);
// console.log(groupids);
//console.log('.............',newgroupdta);
});
}
/* end for loop */
});
groupdata具有低於值
groupdata.... [ { groupType: '1',
id: '199',
unreadMessages: '0',
ownerId: '339',
name: 'xyz' }, { groupType: '1',
id: '200',
unreadMessages: '0',
ownerId: '339',
name: 'second group' }, { groupType: '1',
id: '201',
unreadMessages: '0',
ownerId: '339',
name: 'new one' } ]
groupusers數據是像下面
{ groupUsers: [ { userID: '0' }, { userID: '31' }, { userID: '326' } ] }
基本上我想要查詢的ContactID是326 groupusers 存在,如果沒有,則返回該特定groupdata排列如 {groupdata:[{groupname:,groupid:}]}
/*********************edit***********************/
var count = 0;
var i =0;
function outer(data){
if(count==groupdata.length)break;
var groupname = groupdata[i].name;
var groupid = groupdata[i].id;
var groupType =groupdata[i].groupType;
var getuserdata = {
"groupID" :groupdata[i].id,
"groupType" : groupdata[i].groupType,
"token":req.usersession.token
};
var digest = BASE.utils.hmac("sha1", "A12AA418-1F28-4464-8B67-29CBD02BC45C-F048B14F-F3E3-4F97-A522-F2275A364A0E", JSON.stringify(getuserdata));
var postData = {
"groupID" :groupdata[i].id,
"groupType" : groupdata[i].groupType,
"digest" : digest,
"token" : req.usersession.token
};
var groupUserData = BASE.utils.base64encode(BASE.utils.base64encode(JSON.stringify(postData)));
BASE.request({
url : "http://201.206.158.254:8080/BACKSTAFF/service/getGroupUsers/",
method :"POST",
headers : {
"content-type": "application/json",
},
body :groupUserData
},
function (err,result,groupUserdata) {
console.log(groupUserdata);
});
i++;
outer(groupdata[count++]);
}
/***************end edit *************************/
你能寫正確你想@Sumit – Sumeet
實際到底是什麼我有一個組數據,其中我得到我用來獲取羣組用戶下的羣組用戶,我必須找到一個特定的用戶存在或不存在,如果不是,然後返回特定的數據到數組包括組名,羣組類型,groupid。我希望我清除 –
看起來像同步循環內異步函數調用的又一個問題。 –