.NET XML反序列化有着不同的價值觀

Question

我有以下XML：

<results> 
<row> 
    <id>4990321</id> 
    <field name="First name">John</field> 
    <field name="Last name">Snow</field> 
    <field name="Country">USA</field> 
    <field name="City">San-Diego</field> 
    <field name="Postcode">123456</field> 
    <field name="Email">username@stackoverflow.com</field> 
    <field name="Message">Hello</field> 
</row> 
<row> 
    ... 
<row> 
</results> 

我需要反序列化的對象數組：

public class Employee 
{ 
    public string Id { set; get; } 
    public string Firstname { set; get; } 
    public string Lastname { set; get; } 
    public string Country { set; get; } 
    public string City { set; get; } 
    public string Postcode { set; get; } 
    public string Email { set; get; } 
    public string Message { set; get; } 
} 

我試着使用來實現它XmlElementAttribute和XmlAttributeAttribute，但屬性名爲ElementName不理解XPath，所以我無法獲得特定字段的值（如field[name='Email']）

誰有什麼想法我該怎麼做？不需要XDocument解析。

Answer 1

一個建議是將數據預處理爲一種更友好的通過XSLT轉換進行序列化的表單。這可以在C＃中通過XslCompiledTransform類完成。

使用示例XSL文件將是：

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> 
<xsl:output encoding="UTF-8" indent="yes" method="xml" standalone="no" omit-xml-declaration="no"/> 
    <xsl:template match="results"> 
     <Employees> 
     <xsl:for-each select="row"> 
      <Employee> 
       <Id><xsl:value-of select="id" /></Id> 
       <Firstname><xsl:value-of select="field[@name='First name']" /></Firstname> 
       <Lastname><xsl:value-of select="field[@name='Last name']" /></Lastname> 
       <Country><xsl:value-of select="field[@name='Country']" /></Country> 
      </Employee> 
     </xsl:for-each> 
     </Employees> 
    </xsl:template> 
</xsl:stylesheet> 

（不完整，但足以說明目的）

在你的C＃程序的改造很簡單：

var xslReader = XmlReader.Create(new StringReader(GetXslString())); 
var xmlReader = XmlReader.Create(new StringReader(GetXmlString())); 

var transformedStream = new MemoryStream(); 

var xmlWriter = XmlWriter.Create(transformedStream); 
var xslt = new XslCompiledTransform(); 

xslt.Load(xslReader); 
xslt.Transform(xmlReader, xmlWriter); 

transformedStream.Seek(0, SeekOrigin.Begin); 

// Use your transformedStream to deserialize the object 

.NET小提琴演示此代碼here

這是什麼？ ñ對你的樣本數據，它產生類似輸出：

<?xml version="1.0" encoding="UTF-8" standalone="no"?> 
<Employees> 
    <Employee> 
     <Id>4990321</Id> 
     <Firstname>Jhon</Firstname> 
     <Lastname>Snow</Lastname> 
     <Country>USA</Country> 
    </Employee> 
    <Employee> 
     <Id>4990322</Id> 
     <Firstname>Mike</Firstname> 
     <Lastname>Ross</Lastname> 
     <Country>UK</Country> 
    </Employee> 
</Employees> 

這應該是相當容易的，現在對於任何默認反序列化工具來接管沒有先進的文件選擇器等

Answer 2

你可以反序列化它通過明確聲明的順序元素反序列化使用Order：

[XmlRoot("results")] 
public class Results 
{ 
    [XmlElement("row")] 
    public List<Employee> Employees { get; set; } 
} 

public class Employee 
{ 
    [XmlElement(ElementName = "id", Order = 1)] 
    public string Id { set; get; } 
    [XmlElement(ElementName = "field", Order = 2)] 
    public string Firstname { set; get; } 
    [XmlElement(ElementName = "field", Order = 3)] 
    public string Lastname { set; get; } 
    [XmlElement(ElementName = "field", Order = 4)] 
    public string Country { set; get; } 
    [XmlElement(ElementName = "field", Order = 5)] 
    public string City { set; get; } 
    [XmlElement(ElementName = "field", Order = 6)] 
    public string Postcode { set; get; } 
    [XmlElement(ElementName = "field", Order = 7)] 
    public string Email { set; get; } 
    [XmlElement(ElementName = "field", Order = 8)] 
    public string Message { set; get; } 
} 

然後，您可以反序列化這個如此（其中xml是你的XML字符串）：

var results = new XmlSerializer(typeof(Results)).Deserialize(new StringReader(xml));