MySQL的選擇用戶的地方

Question

我有一個表的用戶：

id | rating 
1  4 
2  -1 
3  12 
4  0 
5  2 
6  0 

如何選擇由等級用戶的位置順序，其中id = N和用戶提供類似的評價在頂部的同一個地方？

UPD：我想輸出：

如果userid = 1，他rank is 2，如果userid = 2，他rank is 5，如果userid = 3，rank is 1 ... 但如果userid = 4或6他們rank are 4因爲利率是相似的。

Answer 1

我想你要查找的評級asll user_id's`：

SELECT id, 
     IF(rating <> @var_rating_prev, (@var_rank:= @var_rank + 1), @var_rank) AS rank, 
     (@var_rating_prev := rating) AS rating 
FROM table_name a,(SELECT @var_rank := 0, @var_rating_prev := 0) r 
ORDER BY rating DESC; 

例@sqlfiddle

如果你不想改變輸出記錄的順序，然後試試這個：

SELECT a.*, b.rank 
FROM test_table a 
    INNER JOIN (
      SELECT id, 
        IF(rating <> @var_rating_prev, (@var_rank:= @var_rank + 1), @var_rank) AS rank, 
        (@var_rating_prev := rating) AS rating 
      FROM test_table a,(SELECT @var_rank := 0, @var_rating_prev := 0) r 
      ORDER BY rating DESC 
     ) b 
     ON a.id = b.id 
ORDER BY a.id; 

Answer 2

SELECT COUNT(*)+1 `rank` 
FROM table_name 
WHERE rating > (SELECT rating 
       FROM table_name 
       WHERE id = N)