mysql_fetch_array

Question

$result = mysql_query('SELECT * FROM phpfox_education_question where subject_id = 2 and ques_id =1'); 
var_dump($result); 
//var_dump result is :- "resource(64) of type (mysql result)" in localhost and web host,but 
while($row = mysql_fetch_array($result)) 
{ 
    var_dump($row); //**NOTHING DISPLAYED in web host server but in localhost** 
} 

Answer 1

試試這個：

$query = "SELECT * FROM phpfox_education_question WHERE subject_id = '2' AND ques_id = '1'"; 
$result = mysql_query($query) or die(mysql_error()); // <--- added this 
echo "Results: ".mysql_num_rows($result)."<br />"; // <--- added this to output result count 
while($row = mysql_fetch_array($result)) 
{ 
    print_r($row); //**NOTHING DISPLAYED in web host server but in localhost** 
} 

這是用來貶值代碼順便說一句

Answer 2

嘗試添加此：

var_dump(mysql_num_rows($result)); 

要查看是否有任何行被提取，如果沒有，那就是你的答案。
順便說一句，在PDO此代碼如下所示：

$db = new PDO('mysql:dbname=default_db_name;host=127.0.0.1',$user,$pass); 
//use prepared statmenets 
$stmt = $db->prepare('SELECT * FROM your_db.phpfox_education_question WHERE subject_id = :subject_id AND ques_id = :ques_id'); 
//pass binds when executing the stmt 
$stmt->execute(array(':subject_id' => 2, ':ques_id' => 1)); 
//number of rows found: 
var_dump($stmt->rowCount()); 
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) 
{//fetch rows as assoc array 
    var_dump($row); 
} 

注意，這是一個基本的例子，還有很多更可以用PDO做

更新：
爲了獲得更多的調試信息，試試這個：

try 
{ 
    $db = new PDO();//connect, pass correct data here 
    $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);//cause PDO to throw PDOExceptions on error 
    $stmt = $db->prepare('SELECT * FROM your_db.phpfox_education_question WHERE subject_id = :subject_id AND ques_id = :ques_id'); 
    $stmt->execute(array(':subject_id' => 1, ':ques_id' => 2)); 
    var_dump($stmt->rowCount()); 
    while($row = $stmt->fetch(PDO::FETCH_ASSOC)) 
    { 
     var_dump($row); 
    } 
} 
catch(PDOException $e) 
{ 
    echo $e->getMessage(); 
    $db = null; 
    return; 
} 
echo 'No problems with query<br/>'; 
$db = null;//disconnecto 

確保沒有錯誤被拋出，如果有，檢查郵件，發現了什麼錯誤，並修復它。如果你找不到解決問題的方法，當然我們會幫助你。