2017-03-06 22 views
0

下面請檢查我的代碼,在其他條件相匹配(測試數據是「K」),但不執行它裏面的語句,而它給錯誤,如 -Python的 - else條件不執行

NameError: name "k" is not defined. 

在如果我給8或9的同時,也沒有在不執行else語句以及同時顯示上面的錯誤,只是表示將使用raw_input而不是input再次

from math import sqrt 
def addition(firstNum,secondNum): 
    total = firstNum+secondNum 
    return total 

def substraction(firstNum,secondNum): 
    total = firstNum-secondNum 
    return total 

def multiplication(firstNum,secondNum): 
    total = firstNum*secondNum 
    return total 

def division(firstNum,secondNum): 
    total = firstNum/secondNum 
    return total 

def root(firstNum): 
    total = (firstNum*firstNum) 
    return total 

menu={} 
menu[" "] = "   --------PYTHON CALCULATOR-------   " 
menu["."] = "~~Main Menu~~" 
menu["1"] = "Addition" 
menu["2"] = "Substraction" 
menu["3"] = "Multiplication" 
menu["4"] = "Division" 
menu["5"] = "Square" 
menu["6"] = "Root" 
menu["7"] = "Exit\n" 

while True: 
    options = menu.keys() 
    options.sort() 
    for entry in options: 
     print entry, menu[entry] 

    selection = input("Please select your correct option: ") 

    if selection == 1: 
     firstNum=input ("\nPlease enter first number : ") 
     secondNum=input("Please enter Second number: ") 

     print "Answer is " , addition(firstNum,secondNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 2: 
     firstNum=input ("\nPlease enter first number : ") 
     secondNum=input("Please enter Second number: ") 
     print "Answer is " ,substraction(firstNum,secondNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 3: 
     firstNum=input ("\nPlease enter first number : ") 
     secondNum=input("Please enter Second number: ") 
     print "Answer is ",multiplication(firstNum,secondNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 4: 
     firstNum=input ("\nPlease enter first number : ") 
     secondNum=input("Please enter Second number: ") 
     print "Answer is " ,division(firstNum,secondNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 5: 
     firstNum=input ("\nPlease enter first number : ") 
     print "Answer is " ,sqrt(firstNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 6: 
     firstNum=input ("\nPlease enter first number : ") 
     print "Answer is " ,root(firstNum) 
     print "--------------------------------------------------------\n\n" 
    elif selection == 7: 
     break 
    else: 
     "Invalid option keyed in..." 
+1

使用'raw_input',而不是'input'。但不要忘記在之後將輸入轉換爲int。 –

+0

請參閱http://stackoverflow.com/questions/23294658/asking-the-user-for-input-until-they-give-a-valid-response,瞭解如何獲得有效的輸入。 –

回答

1

主菜單。 Here's whyraw_input返回由用戶輸入的string,你應該使用再轉換爲int

firstnum = int(raw_input('...')) 
+0

謝謝它的作品...小但重要的修正.... – Prabhu

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