iOS 5谷歌JSON - 如何解析嵌套的對象？

Question

我試圖解析一個YouTube播放列表：

如果我的JSON的結構類似：

{"apiVersion" .... 
"items":[{"id2":"some-id","title":"songtitle", 

我完全能夠通過解析標題：

// Fill array 
NSArray *items = [json objectForKey:@"items"]; 

// Get item from tableData 
NSDictionary *item = [tableData objectAtIndex:[indexPath row]]; 
// Set text on textLabel 
[[cell textLabel] setText:[item objectForKey:@"title"]]; 

但如果JSON是這樣的：

{"apiVersion" .... 
"items":[{"id1": .... "video":{"id2":"some-id","title":"songtitle", 

我怎樣才能達到嵌套目標ct標題？

只是一個簡單的事情，但我現在敲我的頭在這幾個小時。感到沮喪，謝謝你的建議！

[編輯] 這是一個完整的結構：

{ 
    "items": 
    [ 
    { 
    "video": 
      { 
       "title": "Number One", 
       "description": "Description one" 
      },  
      { 
      "title": "Number two", 
       "description": "Description two" 
      }, 
      { 
       "title": "Number three", 
       "description": "Description three" 
      } 
    }, 
    { 
    "video": 
      { 
     "title": "Number One", 
      "description": "Description one" 
      }, 
      { 
       "title": "Number two", 
       "description": "Description two" 
      }, 
      { 
       "title": "Number three", 
       "description": "Description three" 
      } 
    } 

    ] 
} 

Answer 1

的問題是，你的JSON是無效的。所有的titles應該在數組中對嗎？所以他們必須在[]中。您可以使用例如下面的網站「調試」你的JSON：

http://jsonformatter.curiousconcept.com/

此外，在iOS 5中，你可以使用新的內置JSON API。這裏是一個很好的教程是： http://www.raywenderlich.com/5492/working-with-json-in-ios-5

儘管如此，這裏是你的JSON應該什麼樣子我想：

{ 
    "items":[ 
     { 
     "video":[ 
      { 
       "title":"Number One", 
       "description":"Description one" 
      }, 
      { 
       "title":"Number two", 
       "description":"Description two" 
      }, 
      { 
       "title":"Number three", 
       "description":"Description three" 
      } 
     ] 
     }, 
     { 
     "video":[ 
      { 
       "title":"Number One", 
       "description":"Description one" 
      }, 
      { 
       "title":"Number two", 
       "description":"Description two" 
      }, 
      { 
       "title":"Number three", 
       "description":"Description three" 
      } 
     ] 
     } 
    ] 
} 

與您的項目好運;）

Answer 2

NSMutableArray *items = [json valueForkey:@"items"]; 
for(int i =0;i<[items count]; i++) 
{ 
    NSMutableArray *arrtitle = [[[items objectAtIndex:i]valueForkey:@"Video"]copy]; 
    for(int j =0;j<[arrtitle count]; j++) 
    { 
    NSString *title = [[arrtitle objectAtIndex:j]valueForkey:@"title"]; 
    } 
} 

也許這會幫助你。

Answer 3

試試這個：

NSArray *items = [[json valueForkey:@"items"]valueForkey:"video"];