com.google.firebase.database.DatabaseException：無法轉換java.lang.String類型的對象鍵入com.softworld.crib.models.User

Question

我新的火力點，我試圖在實現實時數據庫機器人。我可以寫信給DB成功地但是當我嘗試從數據庫讀取，我得到com.google.firebase.database.DatabaseException: Can't convert object of type java.lang.String to type com.softworld.crib.models.User

我這是怎麼發佈，並從DB

DatabaseReference dbRef = FirebaseDatabase.getInstance().getReference("myUsers"); 
String userId = dbRef.push().getKey(); 

     User user = new User("My New Name","mynewemail@gmail.com",loggedInUser.getPersonPhoto()); 
//how I post to db 
     dbRef.child(userId).setValue(user); 
//how I read from db 
dbRef.child(userId).addValueEventListener(new ValueEventListener() { 
      @Override 
      public void onDataChange(DataSnapshot dataSnapshot) { 
       // This method is called once with the initial value and again 
       // whenever data at this location is updated. 
       List users = new ArrayList<>(); 

       for (DataSnapshot noteDataSnapshot : dataSnapshot.getChildren()) { 
        User user = noteDataSnapshot.getValue(User.class); 
        Toast.makeText(MainActivity.this, user.getPersonEmail(), Toast.LENGTH_LONG).show(); 
        users.add(user); 
       } 

       //Log.d(TAG, "Value is: " + value); 
      } 

      @Override 
      public void onCancelled(DatabaseError error) { 
       // Failed to read value 
       //Log.w(TAG, "Failed to read value.", error.toException()); 
      } 
     }); 

我的User類閱讀看起來是這樣的

public class User { 
    String personName,personEmail; 
    Uri personPhoto; 

    public User() { 
    } 

    public User(String personName, String personEmail, Uri personPhoto) { 
     this.personName = personName; 
     this.personEmail = personEmail; 
     this.personPhoto = personPhoto; 
    } 

    public String getPersonName() { 
     return personName; 
    } 

    public void setPersonName(String personName) { 
     this.personName = personName; 
    } 

    public String getPersonEmail() { 
     return personEmail; 
    } 

    public void setPersonEmail(String personEmail) { 
     this.personEmail = personEmail; 
    } 

    public Uri getPersonPhoto() { 
     return personPhoto; 
    } 

    public void setPersonPhoto(Uri personPhoto) { 
     this.personPhoto = personPhoto; 
    } 
} 

Answer 1

我想你應該改變

dbRef.child(userId).addValueEventListener(new ValueEventListener() { 

到

dbRef.addValueEventListener(new ValueEventListener() { 

爲https://www.firebase.com/docs/android/guide/retrieving-data.html

解釋或者，如果你真的想只得到一個事件這個特定userId的DataSnapshot你得到的是可能已經你要找的用戶，因此在

中使用 .getChildren()

for (DataSnapshot noteDataSnapshot : dataSnapshot.getChildren()) { 

可能是不必要的。