2012-04-01 34 views
1

我正在創建一個跟蹤數據庫,收集信息以報告小時,每天,每週,每月,每年,每級,每班和每層的信息。因此,我有一個名爲tracker的表格,它由一個表格子集組成,反映了不同的報告(即table["ThisHour"]等)。我想知道是否有一種方法可以合併所有這些只添加相同信息的行。下面是我使用的,只有兩個子表(而不是8我上面列出)沿功能:Lua:爲多個子表添加相同的信息 - 更簡單的方法?

function exp_update(xp, gold, str, con, dex, wis, int, luck, bpracs, btrains, pracs, trains, qp) 
local xtable = tracker[playername]["Exp"] 
addto(xtable["ThisHour"],"Exp",xp) 
addto(xtable["ThisHour"],"Gold",gold) 
addto(xtable["ThisHour"],"BonusStr",str) 
addto(xtable["ThisHour"],"BonusCon",con) 
addto(xtable["ThisHour"],"BonusDex",dex) 
addto(xtable["ThisHour"],"BonusWis",wis) 
addto(xtable["ThisHour"],"BonusInt",int) 
addto(xtable["ThisHour"],"BonusLuck",luck) 
addto(xtable["ThisHour"],"BonusPracs",bpracs) 
addto(xtable["ThisHour"],"BonusTrains",btrains) 
addto(xtable["ThisHour"],"Pracs",pracs) 
addto(xtable["ThisHour"],"Trains",trains) 
addto(xtable["ThisHour"],"Qp",qp) 
addto(xtable["ThisHour"],"Quests") 
addto(xtable["ThisLevel"],"Exp",xp) 
addto(xtable["ThisLevel"],"Gold",gold) 
addto(xtable["ThisLevel"],"BonusStr",str) 
addto(xtable["ThisLevel"],"BonusCon",con) 
addto(xtable["ThisLevel"],"BonusDex",dex) 
addto(xtable["ThisLevel"],"BonusWis",wis) 
addto(xtable["ThisLevel"],"BonusInt",int) 
addto(xtable["ThisLevel"],"BonusLuck",luck) 
addto(xtable["ThisLevel"],"BonusPracs",bpracs) 
addto(xtable["ThisLevel"],"BonusTrains",btrains) 
addto(xtable["ThisLevel"],"Pracs",pracs) 
addto(xtable["ThisLevel"],"Trains",trains) 
addto(xtable["ThisLevel"],"Qp",qp) 
addto(xtable["ThisLevel"],"Quests") 
end 

正如你所看到的,這已經是短短兩年子表相當多條線路。對於每個子表,這是14行代碼,或者,如果我將它們全部放入,我希望儘可能少地合併112行代碼。

的AddTo就功能是定義,如果你需要它:

function addto(t,k,v) 
t[k] = t[k] + (v or 1) 
end 

回答

3

我會說這樣做:

local function exp_update_actual(vars) 
    local blocks = {"ThisHour", "ThisLevel"} --Add others as needed. 
    local xtable = tracker[playername]["Exp"] 

    for i, block in ipairs(blocks) do 
    for key, value in pairs(vars) do 
     addto(xtable[block], key, value) 
    end 
    end 
end 

function exp_update(xp, gold, str, con, dex, wis, int, luck, bpracs, btrains, pracs, trains, qp) 
    local vars = 
    { 
    Exp = xp or false, --nil keys won't exist. false ones will. 
    Gold = gold or false, 
    BonusStr = str or false, 
    BonusCon = con or false, 
    BonusDex = dex or false, 
    BonusWis = wis or false, 
    BonusInt = int or false, 
    BonusLuck = luck or false, 
    BonusPracs = bpracs or false, 
    BonusTrains = btrains or false, 
    Pracs = pracs or false, 
    Trains = trains or false, 
    Qp = qp or false, 
    Quests = false, 
    } 
    exp_update_actual(vars); 
end 
+0

正是我一直在尋找。謝謝! – Josh 2012-04-01 01:26:40

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