卡住這個代碼我已經使

Question

這個代碼應該說「請輸入一個新的密碼」，如果你從我創建的列表中輸入一個通用的密碼，然而它沒有，它只是說「密碼接受」，它應該「噸。任何人都可以幫助我嗎？下面是代碼本身：

### Asks user for their name and password ### 

print "Hello, what is your name?" 

### Stores name in variable myName ### 

myName = raw_input() 

print "Nice to meet you "+myName+", please enter a password to continue." 

common_passwords = [ '123456', 'password', '12345', '12345678', 'qwerty', 
        '1234567890', 'baseball', 'dragon', 'football', '1234567', 
        'monkey', 'letmein', 'abc123', '111111', 'mustang', 'access', 
        'shadow', 'master', 'michael', 'superman', '696969', '123123', 
        'batman', 'trustno1'] 

while True: 
    password = raw_input() 
    if len(password) < 8: 
     print "Password is less than 8 characters." 
     print "Your password has to be 8 characters or more." 
     continue 
    found = False 
    for cpass in common_passwords: 
     if cpass == password: 
      print "You have selected a common password" 
      print "Please choose a new password" 
      found = True 
      break 
     if not found: 
      print "Password Accepted" 
      break 

Answer 1

你想要做什麼可能是：

for cpass in common_passwords: 
     if cpass == password: 
      print "You have selected a common password" 
      print "Please choose a new password" 
      found = True 
      break 
if not found: 
     print "Password Accepted" 

因爲要檢查，如果輸入的密碼是common_password發現，如果後不你的循環，密碼是好的。

此外，你可以檢查密碼的存在簡單地：

If password in common_passwords: 
     print "You have selected a common password" 
     print "Please choose a new password" 
else : 
     print "Password Accepted" 

Answer 2

嘗試if password in common_passwords這將考驗所有常用的密碼一氣呵成。 你目前的錯誤是，當你遍歷每一個，如果在commom_passwords中的元素，如果第一個不匹配，它會接受它。