2013-03-02 42 views
0

我想製作一個XML解析器。但是,下面的代碼只是給出了空白輸出。 getElementValue()函數中的「heyya」消息正在打印,它告訴空字符串被返回。請幫忙。在android中解析XML空白字符串

import java.io.IOException; 
import java.io.StringReader; 
import javax.xml.parsers.DocumentBuilder; 
import javax.xml.parsers.DocumentBuilderFactory; 
import javax.xml.parsers.ParserConfigurationException; 
import org.w3c.dom.Document; 
import org.w3c.dom.Element; 
import org.w3c.dom.Node; 
import org.w3c.dom.NodeList; 
import org.xml.sax.InputSource; 
import org.xml.sax.SAXException; 

public class XMLParser { 
     public Document getDomElement(String xml) 
    { 
     Document doc=null; 
     DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
     try{ 

      DocumentBuilder db = dbf.newDocumentBuilder(); 
      InputSource is = new InputSource(); 
      is.setCharacterStream(new StringReader(xml)); 
      doc = db.parse(is); 

     }catch (ParserConfigurationException e){ 
      System.out.println(e.getMessage()); 
      return null; 
     } catch(SAXException e){ 
      System.out.println(e.getMessage()); 
      return null; 
     } catch(IOException e){ 
      System.out.println(e.getMessage()); 
      return null; 
     } 

     return doc; 
    } 

    public String getValue(Element item, String str) 
    { 
     NodeList n = item.getElementsByTagName(str); 
     return this.getElementValue(n.item(0)); 
    } 

    public final String getElementValue(Node elem) 
    { 
     Node child; 
     if(elem!=null){ 
      if(elem.hasChildNodes()){ 
       for(child=elem.getFirstChild(); child!=null; child = child.getNextSibling()){ 
        if(child.getNodeType() == Node.TEXT_NODE){ 
         return child.getNodeValue(); 
        } 
       } 

      } 

     } 
     //System.out.println("heyya"); 
     return ""; 
    } 
} 


class createData 
{ 
    static final String KEY_ID = "id"; //parent node 
    static final String KEY_NAME = "name"; 
    static final String KEY_COST = "cost"; 
    static final String KEY_DESC = "description"; 

    public void createArrayList() 
    { 

     //ArrayList<HashMap<String, String>> userData = new ArrayList<HashMap<String, String>>(); 
     XMLParser parser = new XMLParser(); 
     //obtain xml as string here 
     String xml="<menu>\n\t<item>\n\t\t<id>1</id>\n\t\t<name>Margherita</name>\n\t\t<cost>155</cost>\n\t\t<description>Single cheese topping</description>\n\t</item></menu>\n"; 
     Document doc = parser.getDomElement(xml); 
     NodeList node_L = doc.getElementsByTagName(KEY_ID); 


     for(int i=0; i<node_L.getLength(); i++) 
     { 
      //HashMap<String, String> map = new HashMap<String, String>(); 
      Element e = (Element)node_L.item(i); 
      String name = parser.getValue(e, KEY_NAME); 
      String cost = parser.getValue(e, KEY_COST); 
      String description = parser.getValue(e, KEY_DESC); 
      System.out.println(name+" "+cost+" "+description); 
      //map.put(KEY_NAME, name); 
      //map.put(KEY_COST, cost); 
      //map.put(KEY_DESC, description); 
      //userData.add(map); 
     } 
     System.out.println("hello pop!"); 
     //System.out.println(userData.get(0)); 
    } 

    public static void main(String args[])throws IOException 
    { 
     createData ob =new createData(); 
     ob.createArrayList(); 

    } 
} 
+1

他在3個「ifs」和1個「for」中有一個'return'。它不會一直執行。 – SudoRahul 2013-03-02 10:05:23

+0

@ R.J需要更多咖啡。我在下一個小時停留在這裏;) – Simon 2013-03-02 10:08:56

回答

0

這就是問題所在。

NodeList node_L = doc.getElementsByTagName(KEY_ID); 

您在這裏得到id,但id只是在你的item子標記。替換本 -

​​

注: -你的父節點ITEM而不是ID

你可以得到你的ID,因爲你得到你的其他標籤。

String id = parser.getValue(e, KEY_ID);