將數據插入到數據庫之後將bootstrap模式加載爲提醒

即時通訊新增至php並仍在學習。我試圖定製bootstrap模板，並嘗試將表單連接到數據庫。將數據插入到數據庫之後將bootstrap模式加載爲提醒

insert.php

$con=mysqli_connect("localhost","root","","finalproject"); 
// Check connection 
if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 

$sql="INSERT INTO stokbarang (Merek, Tipe, Harga) 
VALUES 
('$_POST[merek]','$_POST[tipe]','$_POST[harga]')"; 

    if (!mysqli_query($con,$sql)) 
     { 
     die('Error: ' . mysqli_error($con)); 
     } 

header("Location: stock.php");

和所在的頁面形式是stock.php，形式如下：

<form name="sentMessage" class="well" id="contactForm" novalidate action = "insert.php" method = "post"> 
<legend>Masukkan Data</legend> 
    <div class="control-group"> 
    <div class="controls"> 
        <label>Merek Mobil</label> 
       <input type="text" class="form-control" placeholder="Merek mobil" id="merek" required 
         data-validation-required-message="Masukkan Merek mobil" name = "merek"/> 
         <p class="help-block"></p> 
    </div> 
     </div>   
    <div class="control-group"> 
    <div class="controls"> 
    <label>Tipe Mobil</label> 
    <input type="text" class="form-control" placeholder="Tipe Mobil" id="email" required 
          data-validation-required-message="Masukkan tipe mobil" name = "tipe"/> 
       </div> 
     </div>   
       <div class="control-group"> 
        <div class="controls"> 
        <label>Harga</label> 
         <input type="number" class="form-control" placeholder="Harga" 
          id="email" required 
          data-validation-required-message="Masukkan harga mobil" name = "harga"/> 
       </div>  

     <br> 
     <div id="success"> </span></div> <!-- For success/fail messages --> 
     <br> 
     <button type="submit" class="btn btn-primary pull-right">Insert</button><br/><br> 
      </form>

形式是工作，我可以插入數據通過單擊插入按鈕到數據庫。現在我想的形式在stock.php提交到數據庫後

我修改了插入按鈕如下

<button type="submit" class="btn btn-primary pull-right" data-toggle="modal" data-target="#myModal">Insert</button><br/><br>

這裏補充一個模式作爲警報是模態：

<!-- Modal --> 
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true"> 
    <div class="modal-dialog"> 
    <div class="modal-content"> 
     <div class="modal-header"> 
     <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button> 
     <h4 class="modal-title" id="myModalLabel">SUCCESS</h4> 
     </div> 
     <div class="modal-body"> 
     <p>Data Inserted!!</p> 
     </div> 
     <div class="modal-footer"> 
     <button type="button" class="btn btn-default" data-dismiss="modal">Close</button> 

     </div> 
    </div><!-- /.modal-content --> 
    </div><!-- /.modal-dialog --> 
</div><!-- /.modal -->

但它看起來像按鈕只觸發模式出現，而不提交表單到數據庫。成功向數據庫插入數據後（在重定向到stock.php後）出現模態的任何建議？或者也許有更好的方式來重定向後提醒？感謝您的時間，並幫助:)

來源

2013-11-15 abs1

header（「Location：stock.php？success = true」）;如果（isset（$ _GET ['success']）和$ _GET ['success'] =='true'）{echo your alert} – K3rnel31

要用JavaScript警告此模型還是附加它到html？ – K3rnel31

更改標題的位置上insert.php如下：

header("Location: stock.php?sucsess=true");

然後stock.php頭上：

<script type="text/javascript"> 
<?php 
if ($_GET['sucsess'] =='true'){ 
echo '$(function() { 
$("#myModal").dialog(); 
});' 
} 
?> 
</script>

這裏演示只爲警示demo

來源

2013-11-15 20:58:40 K3rnel31

將數據插入到數據庫之後將bootstrap模式加載爲提醒

回答

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