TypeError：'int'對象不是可訂閱的

Question

我已經找過這樣的其他案例，但沒有一個適用於我....或者如果他們這樣做，我不明白如何。

我所試圖做的是通過一個二維數組（這一點）來篩選：

blocks = [ 
[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ], 

[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ] 

，並找出當前的部分是什麼。對不起，如果我的代碼有點草率，我是python的新手。這是我的代碼（部分），

def drawBlock(): 
for blockL1 in blocks: 
    for blokL2 in blocks: 
     if blocks[blockL1[blockL2[1]]] == 0: 
      pygame.draw.rect(screen, (0, 255, 255), Rect((blockL1 * 32, blockL2 *32), (32, 32))) 
      pygame.draw.rect(screen, color, Rect(i * 32,)) 
     global blockL2 
     blockL2 += 1 
    global blockL1 
    blockL1 += 1 

Answer 1

你有幾個問題在這裏進行。

主要問題是您使用for blank in blank_holder。

當你寫

for blockL1 in blocks: 

它幾乎等同於編寫

for ii in range(len(blocks)): 
    blockL1 = blocks[ii] 
    ... 

意味着blockL1不是一個整數，或塊的指標..它是塊的元素！

它的值將如下所示：[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ]

這是一個列表的列表...其中作爲blocks是包含列表列出的名單...是啊

當你寫

for blockL1 in blocks: 
    for blockL2 in blocks: 

的blockL2的價值將是一個單獨的列表[0]

假設你想看看在包含在blockL2的一個值，你可以改變：

if blocks[blockL1[blockL2[1]]] == 0: 

到：

if blockL2[0] == 0: # the 1 index would go out of bounds for a list length 1 

但是這個代碼看起來像你需要的blockL1和blockL2的索引值，所以我建議你遍歷列表（意思是ints）...不是他們的elemnents

def drawBlock(): 
    for blockL1 in range(len(blocks)): 
     for blockL2 in range(len(blockL1)): 
      if blocks[blockL1[blockL2[0]]] == 0: 
       pygame.draw.rect(screen, (0, 255, 255), Rect((blockL1 * 32, blockL2 *32), (32, 32))) 

希望這有助於一些！