Symfony findAll（）返回錯誤類型的結果集

Question

我正在使用php symfony框架。我想從用戶表中獲取所有行。這就是爲什麼我寫了

$repository = $this->getDoctrine()->getRepository(User::class); 
$users = $repository->findAll(); 

但它的數組返回一個奇怪的數組類型。

Array ( 
      [0] => AppBundle\Entity\User Object ([id:AppBundle\Entity\User:private] => 1 [roll:AppBundle\Entity\User:private] => 1 [name:AppBundle\Entity\User:private] => kumar [password:AppBundle\Entity\User:private] => 123456) 
      [1] => AppBundle\Entity\User Object ([id:AppBundle\Entity\User:private] => 2 [roll:AppBundle\Entity\User:private] => 2 [name:AppBundle\Entity\User:private] => arpan [password:AppBundle\Entity\User:private] => 1234) 
      [2] => AppBundle\Entity\User Object ([id:AppBundle\Entity\User:private] => 3 [roll:AppBundle\Entity\User:private] => 3 [name:AppBundle\Entity\User:private] => Bumba [password:AppBundle\Entity\User:private] => abcd) 
     ) 

現在，如果我嘗試返回新的響應（json_encode（$用戶）），則返回[{}，{}，{}]。幫我。

Answer 1

它返回的是一組對象。一般來說，這是您想要的自動綁定/保溼所有您創建的實體，因此您現在可以撥打$result->getFoo()。

但是，你似乎想JSON結果，你應該叫->getArrayResult()而不是->findAll()

像這樣：

$query = $this->getDoctrine() 
     ->getRepository('User entity namespace') // probably AppBundle/Entity/User 
     ->createQueryBuilder('u') 
     ->getQuery(); 
$result = $query->getArrayResult(); 

我高度建議您閱讀文檔從上到下約10倍尤其是Symfony的&學說部分https://symfony.com/doc/current/doctrine.html