當傳遞變量時，GeoPoint不能正常工作

Question

我是Android和Java新手，在嘗試發送變量時遇到了創建GeoPoint的麻煩，但是當我發送一個字面值時，它很好。

在下面的代碼塊，所述的烤麪包消息顯示正確的緯度（來自的strings.xml檢索

如何可以使用變量I設定緯度？

Integer intLat = Integer.valueOf(R.string.MexCityLat); 
Toast.makeText(HelloGoogleMapsActivity.this, intLat, Toast.LENGTH_SHORT).show(); 

GeoPoint point = new GeoPoint(intLat , -99120000); //this puts my point near North Pole 
//GeoPoint point = new GeoPoint(19240000, -99120000); //this puts my point in Mexico City 

OverlayItem overlayitem = new OverlayItem(point, "Hola, Mundo!", "I'm in Mexico City!"); 

Answer 1

的GeoPoint

public GeoPoint(int latitudeE6,int longitudeE6) 

構造一個具有給定經度和緯度的GeoPoint，以微點（度* 1E6）度量。

參數：

latitudeE6 - The point's latitude. This will be clamped to between -80 degrees and +80 degrees inclusive, in order to maintain accuracy in the Mercator projection. 
longitudeE6 - The point's longitude. This will be normalized to be greater than -180 degrees and less than or equal to +180 degrees. 

也可參考此link如何雙轉換，浮到的GeoPoint。並確保你得到正確的價值intLat