笨更新多行的where子句

Question

當我嘗試這種代碼：

$query = ''; 
foreach ($data as $row) 
{ 
    $where = array(
       'community_id' => $row->id, 
       'user_id'  => $this->session->user_id, 
       'status'  => 'invited_to_join', 
      ); 
    $update = array(
       'status' => 'joined', 
      ); 
    $query .= $this->db->set($update)->where($where)->get_compiled_update('community_members').'; '; 
} 
if ($query) 
{ 
    return $this->db->query($query); 
} 

它給我的錯誤：

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'UPDATE community_members SET status = 'joined' WHERE community_id = '18' A' at line 4

this answer使用簡單的查詢使用CASE，但我不知道如何將其轉換爲Codeigniter的查詢生成器。

Answer 1

試試這個例子;

您可以直接在這裏像這樣使用數組$data['id']，無需循環使用作爲我的冠癭

 $this->db->set('status','joined'); 
     $this->db->where('community_id',$data['id']); 
     $this->db->where('user_id',$this->session->user_id); 
     $this->db->where('status','invited_to_join'); 
     $this->db->update('community_members'); 

Answer 2

您還可以使用where條款是這樣的：

$where = "'community_id'=".$data['id']." AND user_id=".$this->session-user_id." AND status='invited_to_join'"; 

    $this->db->set('status','joined'); 
    $this->db->where($where); 
    $this->db->update('community_members'); 

謝謝！