如何在Webdriver中提交表單後等待頁面加載。我正在使用firefox驅動程序

Question

我正試圖自動化一個測試用例，我通過單擊圖像來提交表單。

頁面重新加載我不能夠在網頁上

我使用Java，Firefox的驅動程序的任何元素進行交互後。

代碼卡住了，根本無法識別元素。

是否有像QTP硒一樣的webdriver的等待機制？

Answer 1

http://release.seleniumhq.org/selenium-remote-control/0.9.0/doc/java/

waitForpageLoad（）

Answer 2

我認爲硒2，你並不需要一個表格後等待使用Firefox的webdriver提交。

 element.sendKeys("34344343"); 
    webDriver.findElement(By.id("searchSubmitButton")).click(); 

WebElement columnInPostedPage = webDriver.findElement(By.xpath("//div[@id='content']/table/tbody/tr[2]/td[3]")); // 

如果內容是由JavaScript加載頁面加載後，你可以做這樣的事情的內容

 query.submit(); 

    long end = System.currentTimeMillis() + 5000; 
    while (System.currentTimeMillis() < end) { 
     WebElement result = webDriver.findElement(By.id("content")); 
     if (result.isDisplayed()) { 
      break; 
     } 
     //Thread.sleep(1000); 
    }   

    WebElement columnInPostedPage = webDriver.findElement(By.xpath("//div[@id='content']/table/tbody/tr[2]/td[3]")); // 

Answer 3

只需使用FluentWait類：

/** 
* An implementation of the {@link Wait} interface that may have its timeout 
* and polling interval configured on the fly. 
* 
* <p>Each FluentWait instance defines the maximum amount of time to wait for 
* a condition, as well as the frequency with which to check the condition. 
* Furthermore, the user may configure the wait to ignore specific types of 
* exceptions whilst waiting, such as 
* {@link org.openqa.selenium.NoSuchElementException NoSuchElementExceptions} 
* when searching for an element on the page. 
* 
* <p>Sample usage: 
* <code><pre> 
* // Waiting 30 seconds for an element to be present on the page, checking 
* // for its presence once every 5 seconds. 
* Wait<WebDriver> wait = new FluentWait<WebDriver>(driver) 
*  .withTimeout(30, SECONDS) 
*  .pollingEvery(5, SECONDS) 
*  .ignoring(NoSuchElementException.class); 
* 
* WebElement foo = wait.until(new Function<WebDriver, WebElement>() { 
*  public WebElement apply(WebDriver driver) { 
*  return driver.findElement(By.id("foo")); 
*  } 
* }); 
* 

或WebDriverWait。

Answer 4

for (int second = 0;; second++) { 
      if (second >= 60) fail("timeout"); 
      try { if (isElementPresent(By.linkText("element"))) break; } catch (Exception e) {} 
      Thread.sleep(1000); 
     } 

Answer 5

2年後，Ruby實現：

wait = Selenium::WebDriver::Wait.new(:timeout => 10) 
wait.util { 
    @driver.execute_script("return document.readyState;") == "complete" 
}