Python多次的隨機數

Question

import random 

def main(): 
    uinput() 

def uinput(): 
    times = int(input('How many numbers do you want generated?')) 
    number1 = int(input('Put in the first number:')) 
    number2 = int(input('Put in the second number:')) 
    rnumber = random.randint(number1, number2) 
    print (rnumber) 



main() 

我在Python中搞亂了，我想讓我的程序生成隨機數。正如你所看到的，我已經完成了這一點。接下來我想要做的是讓它生成多個隨機數，這取決於「用戶」想要生成多少個數字。我會如何去做這件事？我假設需要一個循環。

Answer 1

使用「for」循環。例如：

for i in xrange(times): 
    # generate random number and print it 

Answer 2

這將產生一系列number1隨機整數的列表number2

rnumber = [random.randint(number1, number2) for x in range(times)] 

欲瞭解更多信息，看看List Comprehension.

Answer 3

使用生成器和迭代：

import random 
from itertools import islice 

def genRandom(a, b): 
    while True: 
     yield random.randint(a, b) 


number1 = int(input('Put in the first number:')) 
number2 = int(input('Put in the second number:')) 
total = int(input('Put in how many numbers generated:')) 

rnumberIterator = islice(genRandom(number1, number2), total) 

Answer 4

此代碼選擇一個rando m號碼：

import random 
x = (random.randint(1, 50)) 
print ("The number is ", x) 

重複該代碼6次以選擇6個隨機數。

Answer 5

我會建議使用一個循環，只會增加現有的字符串：

import random 
from random import randint 
list="" 
number1=input("Put in the first number: ") 
number2=input("Put in the second number: ") 
total=input("Put in how many numbers generated: ") 
times_run=0 
while times_run<=total: 
    gen1=random.randint(number1, number2) 
    list=str(list)+str(gen1)+" " 
    times_run+=1 
print list